问题
So I know Python strings are immutable, but I have a string:
c['date'] = "20110104"
Which I would like to convert to
c['date'] = "2011-01-04"
My code:
c['date'] = c['date'][0:4] + "-" + c['date'][4:6] + "-" + c['date'][6:]
Seems a bit convoluted, no? Would it be best to save it as a separate variable and then do the same? Or would there basically be no difference?
回答1:
You could use .join()
to clean it up a little bit:
d = c['date']
'-'.join([d[:4], d[4:6], d[6:]])
回答2:
You are better off using string formatting than string concatenation
c['date'] = '{}-{}-{}'.format(c['date'][0:4], c['date'][4:6], c['date'][6:])
String concatenation is generally slower because as you said above strings are immutable.
回答3:
Dates are first class objects in Python, with a rich interface for manipulating them. The library is datetime.
> import datetime
> datetime.datetime.strptime('20110503','%Y%m%d').date().isoformat()
'2011-05-03'
Don't reinvent the wheel!
回答4:
s = '20110104'
def option_1():
return '-'.join([s[:4], s[4:6], s[6:]])
def option_1a():
return '-'.join((s[:4], s[4:6], s[6:]))
def option_2():
return '{}-{}-{}'.format(s[:4], s[4:6], s[6:])
def option_3():
return '%s-%s-%s' % (s[:4], s[4:6], s[6:])
def option_original():
return s[:4] + "-" + s[4:6] + "-" + s[6:]
Running %timeit
on each yields these results
- option_1: 35.9 ns per loop
- option_1a: 35.8 ns per loop
- option_2: 36 ns per loop
- option_3: 35.8 ns per loop
- option_original: 36 ns per loop
So... pick the most readable because the performance improvements are marginal
回答5:
I'd probably do so this way, not that there's a great deal of gain:
d = c['date']
c['date'] = '%s-%s-%s' % (d[:4], d[4:6], d[6:])
The big improvement (imho) is avoiding string concatenation.
回答6:
I'm not usually the guy saying "use regex," but this is a good use-case for it:
import re
c['date']=re.sub(r'.*(\w{4})(\w{2})(\w{2}).*',r"\1-\2-\3",c['date'])
回答7:
I am not sure if you want to convert it to a proper datetime object or rather just hard code the format, you can do the following:
from datetime import datetime
result = datetime.strptime(c['date'], '%Y%m%d')
print result.date().isoformat()
Input: '20110104'
Output: '2011-01-04'
来源:https://stackoverflow.com/questions/14387947/fastest-way-to-insert-these-dashes-in-python-string