Inheritance in Arduino Code

问题

I'm writing some Arduino code and attempting to use inheritance in some classes. I have a class "Actor" (my base class) and a class "Marble" (which inherits from Actor). Here are the header files:

Actor.h:

#ifndef Actor_h
#define Actor_h

#include "Arduino.h"

class Actor
{
  public:
    Actor();
    void speak();
  private:
};
#endif

Marble.h:

#ifndef Marble_h
#define Marble_h

#include "Arduino.h"
#include "Actor.h"

class Marble : public Actor {
  public:
    Marble();
    virtual void speak();    
  private:
};
#endif

Actor.cpp:

#include "Arduino.h"
#include "Actor.h"

Actor::Actor()
{
}

void Actor::speak() {
  Serial.println("Actor"); 
}

Marble.cpp:

#include "Arduino.h"
#include "Marble.h"

void Marble::speak() {
  Serial.println("Marble"); 
}

And finally, in the loop function I do:

void loop() {
  Marble marble;
  Actor children[2];
  children[0] = marble;

  children[0].speak();

Which results in "Actor" being printed.

I discovered this nice link which seems similar to my issue, but the resolution does not seem to work for me: http://arduino.cc/forum/index.php?topic=41884.0

So. It seems like when I create my array of "Actors" and try and stick Marble in there it gets cast to an Actor, or something like that. Problem is, I'll have a few different characters that will all inherit from "Actor" and I'd like an array of them to iterate over and call overridden methods on them.

So, perhaps the problem is how I'm approaching this problem, or maybe there's some syntax errors? I don't know!

Thanks for your help, Kevin

回答1:

You need to declare speak as virtual in the Actor class, not just in the Marble class; without that, Actor::speak is a non-virtual function, so you will always be called in preference to the virtual Marble::speak.

For what it's worth, this has nothing to do with the Arduino: it's just a straight C++ issue.

回答2:

Your problem is that children is an array of type Actor. The line children[0] = marble is taking a Marble object, converting it to an Actor object and copying the results to children[0]. Since the call to children[0].speak() is on an Actor, you get the Actor version.

In order for this to work the way you want, you need to copy a pointer or reference to the object rather than the object itself. That is, you want something like `Actor* children[2]':

Marble marble;
Actor* children[2];
children[0] = &marble;

children[0]->speak();

Of course if children has scope outside of loop, this will fail utterly and you'll need to use new to create your marbles.

Better yet, assuming Arduino has the STL, you should use vector and shared_ptr or something similar.

[Update] As Philip notes, this will also require that the speak method in Actor be declared virtual.

来源：https://stackoverflow.com/questions/14883128/inheritance-in-arduino-code

标签

c++

inheritance

arduino