Description
Given two strings S
and T
. Count the number of distinct subsequences of S
which equals T
.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE"
is a subsequence of "ABCDE"
while "AEC"
is not)
Example
Example 1:
Input: S = "rabbbit", T = "rabbit" Output: 3 Explanation: You could remove any 'b' in S, so there are 3 ways to get T.
Example 2:
Input: S = "abcd", T = "" Output: 1 Explanation: There is only 1 way to get T - remove all chars in S.
Challenge
Do it in O(n^2) time and O(n) memory.
O(n^2) memory is also acceptable if you do not know how to optimize memory.
public int numDistinct(String S, String T) { if (S == null || T == null) { return 0; } int[][] nums = new int[S.length() + 1][T.length() + 1]; for (int i = 0; i <= S.length(); i++) { nums[i][0] = 1; } for (int i = 1; i <= S.length(); i++) { for (int j = 1; j <= T.length(); j++) { nums[i][j] = nums[i - 1][j]; if (S.charAt(i - 1) == T.charAt(j - 1)) { nums[i][j] += nums[i - 1][j - 1]; } } } return nums[S.length()][T.length()]; }
来源:https://www.cnblogs.com/FLAGyuri/p/12078446.html