Pure functional Random number generator - State monad

问题

The book 'Functional Programming in Scala' demonstrates an example of pure functional random number generator as below

trait RNG {
    def nextInt: (Int, RNG)
}

object RNG {
    def simple(seed: Long): RNG = new RNG {
        def nextInt = {
            val seed2 = (seed*0x5DEECE66DL + 0xBL) &
                        ((1L << 48) - 1)
            ((seed2 >>> 16).asInstanceOf[Int],
             simple(seed2))
        }
    }
}

The usage will look like

val (randomNumber,nextState) = rng.nextInt

I do get the part that it's a pure function as it returns the next state and leaves it on the API client to use it to call nextInt the next time it would need a random number but what I did not understand is 'how will the first random number be generated as we must provide seed at least once.

Should there be another function to lift seed to get a RNG? And if so then how do we expect the client of this API to know about it (because in the non-functional implementation user just calls nextInt and the state is maintained by API)

Can someone give a full example of pure functional random number generator in Scala and perhaps relate it to state Monad in general.

回答1:

That random generator RNG is pure functional, for the same inputs you get always the same outputs. The non-pure-functional part is left for the user of that API (you).

To use the RNG in a pure-functional way you have to initialize it always with the same initial value, but then you will always get the same sequence of numbers, which is not so useful.

Otherwise, you will have to rely the initialization of RNG to an external system (usually the wall-clock time) and so introducing side effects (bye pure functional).

val state0 = RNG.simple(System.currentTimeMillis)

val (rnd1, state1) = state0.nextInt
val (rnd2, state2) = state1.nextInt
val (rnd3, state3) = state2.nextInt

println(rnd1, rnd2, rnd3)

[EDIT]

Inspired by the answer of @Aivean, I created my version of randoms Stream:

def randoms: Stream[Int] = Stream.from(0)
  .scanLeft((0, RNG.simple(System.currentTimeMillis)))((st, _) => st._2.nextInt)
  .tail
  .map(_._1)

println(randoms.take(5).toList)
println(randoms.filter(_ > 0).take(3).toList)

回答2:

In addition, your example nicely combines with Scala streams:

  def randStream(r: RNG): Stream[Int] = r.nextInt match {
    case (value, next) => value #:: randStream(next)
  }

  val rng = randStream(RNG.simple(123))
  println(rng.take(10).toList)
  println(rng.take(5).toList)

回答3:

Can someone give a full example of pure functional random number generator in Scala and perhaps relate it to state Monad in general.

This is a purely functional RNG.

val state0 = RNG.simple(1234)
val (r1, state1) = state0.nextInt
val (r2, state2) = state1.nextInt
// etc.
val (x, _) = state1.nextInt
assert (x == r2)

回答4:

A recursive function, derived from @Aivean Stream based function,

def rand(n: Int, r: RNG): List[Int] = { 
  if (n < 0) List() 
  else {
    val (value, next) = r.nextInt
    value :: rand(n-1, next) 
  }
}

To get 5 random values,

rand(5, RNG.simple(System.currentTimeMillis) )

来源：https://stackoverflow.com/questions/31818787/pure-functional-random-number-generator-state-monad

标签

scala

functional-programming

monads

state-monad