Why can I collect a parallel stream to an arbitrarily large array but not a sequential stream?

问题

From answering this question, I ran into a peculiar feature. The following code works as I assumed it would (the first two values within the existing array would be overridden):

Integer[] newArray = Stream.of(7, 8)
                           .parallel()
                           .toArray(i -> new Integer[] {1, 2, 3, 4, 5, 6});

System.out.println(Arrays.toString(newArray));

Output:

[7, 8, 3, 4, 5, 6]

However, attempting this with a sequential stream throws an IllegalStateException:

Integer[] newArray = Stream.of(7, 8)
                           .toArray(i -> new Integer[] {1, 2, 3, 4, 5, 6});

System.out.println(Arrays.toString(newArray));

Output:

Exception in thread "main" java.lang.IllegalStateException: Begin size 2 is not equal to fixed size 6
    at java.base/java.util.stream.Nodes$FixedNodeBuilder.begin(Nodes.java:1222)
    at java.base/java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:483)
    at java.base/java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:474)
    at java.base/java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:550)
    at java.base/java.util.stream.AbstractPipeline.evaluateToArrayNode(AbstractPipeline.java:260)
    at java.base/java.util.stream.ReferencePipeline.toArray(ReferencePipeline.java:517)
    at test/test.Test.main(Test.java:30)

I'm curious as to why the sequential stream does not overwrite elements of the array as the parallel stream does. I searched around a bit and was not able to find documentation regarding this, but I assume it exists somewhere.

回答1:

The generator function is required to produce "a new array of the desired type and the provided length." If you don't comply with the spec, behavior is undefined.

来源：https://stackoverflow.com/questions/49760818/why-can-i-collect-a-parallel-stream-to-an-arbitrarily-large-array-but-not-a-sequ