How to unpack multiple tuples in function call

问题

If I have a function def f(a, b, c, d) and two tuples, each with two elements, is there any way to unpack these tuples so that I can send their values to the function?

f(*tup1, *tup2)

回答1:

As of the release of Python 3.5.0, PEP 448 "Additional Unpacking Generalizations" makes the natural syntax for this valid Python:

>>> f(*tup1, *tup2)
1 2 2 3

In older versions of Python, you can need to concatenate the tuples together to provide a single expanded argument:

>>> tup1 = 1, 2
>>> tup2 = 2, 3
>>> def f(a, b, c, d):
        print(a, b, c, d)

>>> f(*tup1+tup2)
1 2 2 3

回答2:

Another approach using chain

>>> from itertools import chain
>>> def foo(a,b,c,d):
        print a,b,c,d


>>> tup1 = (1,2)
>>> tup2 = (3,4)
>>> foo(*chain(tup1,tup2))
1 2 3 4

回答3:

f(tup1[0],tup1[1],tup2[0],tup2[1]) #not good enough?

来源：https://stackoverflow.com/questions/10564801/how-to-unpack-multiple-tuples-in-function-call