Multiply 2 double[][] Matrices Using Streams

白昼怎懂夜的黑 提交于 2019-12-21 06:22:08

问题


I'm wondering what the most compact and efficient way to multiple 2 double[][] arrays matrices using streams. The approach should follow matrix multiplication rules as illustrated here: http://www.mathwarehouse.com/algebra/matrix/multiply-matrix.php

Here's one way to do it using for loops ('this' is the first matrix'):

final int nRows = this.getRowDimension();
final int nCols = m.getColumnDimension();
final int nSum = this.getColumnDimension();

final double[][] outData = new double[nRows][nCols];
// Will hold a column of "m".
final double[] mCol = new double[nSum];
final double[][] mData = m.data;

// Multiply.
for (int col = 0; col < nCols; col++) {
    // Copy all elements of column "col" of "m" so that
    // will be in contiguous memory.
    for (int mRow = 0; mRow < nSum; mRow++) {
        mCol[mRow] = mData[mRow][col];
    }

    for (int row = 0; row < nRows; row++) {
        final double[] dataRow = data[row];
        double sum = 0;
        for (int i = 0; i < nSum; i++) {
            sum += dataRow[i]
                    * mCol[i];
        }
        outData[row][col] = sum;
    }
}

The procedure should fit the following test data:

    double[][] md1 = { { 4d, 8d }, { 0d, 2d }, { 1d, 6d } };
    double[][] md2 = { { 5d, 2d, 5d, 5d }, { 9d, 4d, 5d, 5d } };

    double[][] md1 = { { 4d, 8d }, { 0d, 2d }, { 1d, 6d } };
    double[][] md2 = { { 5d }, { 9d } };

回答1:


A more compact and readable solution is to create a Stream over the rows of the first matrix, map each row to the result of multiplying it with the second matrix column and collect that back into a double[][].

public static void main(String[] args) {
    double[][] m1 = { { 4, 8 }, { 0, 2 }, { 1, 6 } };
    double[][] m2 = { { 5, 2 }, { 9, 4 } };

    double[][] result = Arrays.stream(m1).map(r -> 
        IntStream.range(0, m2[0].length).mapToDouble(i -> 
            IntStream.range(0, m2.length).mapToDouble(j -> r[j] * m2[j][i]).sum()
    ).toArray()).toArray(double[][]::new);

    System.out.println(Arrays.deepToString(result));
}

This will calculate m1 * m2 and the result will be in result. For the multiplication of each row, we can't create a Stream with Arrays.stream of the second matrix since this would create a Stream over the rows when we need a Stream over the columns. To counteract that, we simply go back to using an IntStream over the indexes.




回答2:


I created a BiFunction that performs the multiplication using IntStream.range(). If anyone has anything more compact I would love to see it. Here it is:

public static BiFunction<ArrayMatrix, ArrayMatrix, ArrayMatrix> multiply(boolean parallel) {

    return (m1, m2) -> {
        // checkMultiplicationCompatible(m1, m2);

        final int m1Rows = m1.getRowDimension();
        final int m2Rows = m2.getRowDimension();
        final int m1Cols = m1.getColumnDimension();
        final int m2Cols = m2.getColumnDimension();

        double[][] a1 = m1.getData();
        double[][] a2 = m2.getData();

        final double[][] result = new double[m1Rows][m2Cols];

        // Buffer for the tranpose of each md2 column
        final double[] transpose = new double[m1Rows];

        range(0, m2Cols).forEach(m2Col -> {
            range(0, m2Rows).forEach(m2Row -> {
                transpose[m2Row] = a2[m2Row][m2Col];
            });

            range(0, m1Rows).forEach(row -> {
                final double[] dataRow = a1[row];
                double sum = 0;
                for (int m1Col = 0; m1Col < m1Cols; m1Col++) {
                    sum += dataRow[m1Col]
                            * transpose[m1Col];
                }
                result[row][m2Col] = sum;
            });
        });

        return new ArrayMatrix(result, false);
    };
}


来源:https://stackoverflow.com/questions/34774384/multiply-2-double-matrices-using-streams

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