In Grails, how can I get the request URI including request parameters?

问题

If my incoming URL is this....

http://data-api:8080/policies/400?output=json

...what method on the request object in Grails will give me this...

/policies/400?output=json

I know request.forwardURI gives everything up to ?, but does not include the parameters

回答1:

request.requestURI + '?' + request.queryString 

回答2:

I found the difference of request.requestURI between in Jetty and in WebLogic 10.2.

So, I use helper class :

def helper = new org.springframework.web.util.UrlPathHelper()
def reqURI = helper.getOriginatingRequestUri(request)
def qryStr = helper.getOriginatingQueryString(request)

回答3:

it's maybe not the best solution, but I use the following:

request.forwardURI+'?'+request.'javax.servlet.forward.query_string'

来源：https://stackoverflow.com/questions/8605885/in-grails-how-can-i-get-the-request-uri-including-request-parameters