问题
From my background in imperative programming, I'm accustomed to doing
for (i = 0; i < 1000000; i++) {
for (j = i + 1; j < 1000000; j++) {
doSomething(array[i], array[j])
}
}
to examine all unique pairs in a million element array. doSomething
is some operation that yields trivial results on diagonal and symmetric or antisymmetric results off diagonal--- that's why I only want to work on the upper triangle. (There's a minor variant of this where the i == j
case is interesting; that's easy to fix.)
I find myself oddly stuck trying to do this in Scala. I have a large List
and want to do something to all the pairwise combinations, but
list.flatMap(x => list.map(y => doSomething(x, y))
includes all the redundant or trivial cases (a factor of two too much work) and
(0 until 1000000).flatMap({i =>
(0 until 1000000).map({j =>
doSomething(list(i), list(j))
})
})
would be very wrong because Lists are not random access (a factor of N^2 too much work). I could convert my Lists
to Arrays
, but that feels like it misses the point. Lists
are linked lists, so the j + 1
element from my imperative example is only a step away from the i
I'm currently examining. I'm sure I could write an efficient upper-triangular loop over linked lists in C/Python/whatever.
I suppose I can just swallow the factor of two for now, but this is such a common situation to run into that it feels like there ought to be a nice solution to it.
Also, does this "upper-triangular loop" have a common name? I couldn't find a good search string for it.
Edit: Here's an example of a bad solution:
list.zipWithIndex.flatMap({case (x, i) =>
list.zipWithIndex.map({case (y, j) =>
if (j > i)
doSomething(x, y)
else
Nil
})
})
because it still visits the unwanted nodes.
回答1:
You may want to look at the Vector data type, it allows for quick indexed based look up.
Also, there is a built in combinations method that will give you what it looks like you are looking for.
scala> (1 to 3).combinations(2).mkString(" ")
res1: String = Vector(1, 2) Vector(1, 3) Vector(2, 3)
回答2:
You can use pattern matching and tail recursion in the following way:
@tailrec def walk[T](list: Seq[T]): Unit =
list match {
case head :: tail =>
tail.foreach(doSomething(head, _))
walk(tail)
case Nil =>
}
回答3:
About this part of the question:
Also, does this "upper-triangular loop" have a common name? I couldn't find a good search string for it.
The common name for "upper-triangular loop" is triangular matrix. (as described in wikipedia)
... a triangular matrix is a special kind of square matrix. A square matrix is called lower triangular if all the entries above the main diagonal are zero. Similarly, a square matrix is called upper triangular if all the entries below the main diagonal are zero.
来源:https://stackoverflow.com/questions/18707121/upper-triangular-loop-idiom-for-scala-lists