Guava - How to remove from a list, based on a predicate, keeping track of what was removed?

问题

I have an ArrayList to be filtered, and various Guava Predicates to filter it with. This list will have only 50-100 elements.

I was planning on Iterables.removeIf using each predicate in turn. It is perhaps not maximally efficient but never mind (at least removeIf has some optimization for RandomAccess lists)

For debugging, I want to concisely log what each predicate did. e.g.

Pred0 removed [a, c, g]
Pred1 removed []
Pred2 removed [b, f]

There are some obvious hack solutions but what would you suggest as the cleanest?

For bonus points, it should be reasonably efficient too. ;)

回答1:

I would capture the removed elements in your Predicate code.

List<String> removedElements = Lists.newArrayList();
final Iterables.removeIf(list, new Predicate<String>() {
    @Override
    public boolean apply(String input) {
        if ("a".equals(input)) {
            removedElements.add(input);
            return true;
        }
        return false;
    }
});

回答2:

This may be an occasion when using a loop is simplest.

List<MyType> list =
Predicate<MyType>[] predicates =
Map<Predicate, List<MyType>> removed = 
      new LinkedHashMap<Predicate, List<MyType>>();
for(Iterator<MyType> iter=list.iterator();list.hasNext();) {
   MyType mt = iter.next();
   for(Predicate<MyType> pred: predicates) 
       if(pred.apply(mt)) {
          List<MyType> mts = removed.get(pred);
          if(mts == null)
              removed.put(pred, mts = new ArrayList<MyType>());
          mts.add(mt);
          iter.remove();
          break;
       }
 }

回答3:

I'd investigate in observable predicates. The idea: everytime, a predicates apply method is about to return true, it will fire a notification to listeners:

Iterable<?> iterable = getIterable();
Collection<ObservablePredicate> predicates = getPredicates();
PredicatesLogger log = new PredicatesLogger(predicates);  // listens to all predicates
for (ObservablePredicate pred : predicates) {
  Iterables.removeIf(iterable, pred);
  log.print();
  log.reset();
}

The ObservableLogger is a decorator for Predicate :

public class ObservableLogger implements Predicate {
  private Predicate predicate;

  private List<Listener> listeners = new ArrayList<Listener>();
  // usual stuff for observer pattern

  @Override
  public boolean apply(Object input) {
    boolean result = predicate.apply(input);
    fire(result);
    return result;
  }

  // a fire method
}

The PredicateLogger needs one constructor that adds itself as a listener to the predicates. It will receive the notifications and cache the predicates that fired the events (the Event class needs an appropriate field for that information). print will create the log message, reset will clear the loggers cache (for the next run).

回答4:

I agree with Peter's anwser.

But if you want to have fun, you could also wrap each of your predicate inside a predicate which would delegate to the wrapped predicate, and store the values for which true is returned inside a Map<Predicate, List<Foo>> removedByPredicate :

class PredicateWrapper implements Predicate<Foo> {
    private Predicate<Foo> delegate;

    public PredicateWrapper(Predicate<Foo> delegate) {
        this.delegate = delegate;
    }

    @Override
    public boolean apply(Foo foo) {
        boolean result = delegate.apply(foo);
        if (result) {
            List<Foo> objectsRemoved = removedByPredicate.get(delegate);
            if (objectsRemoved == null) {
                objectsRemoved = Lists.newArrayList();
                removedByPredicate.put(delegate, objectsRemoved);
            }
            objectsRemoved.add(foo);
        }
        return result;
    }
}

回答5:

I guess you need:

Predicate<XXX> predicate1 = new Predicate<XXX>(){  
    @Override  
    public boolean apply(XXX input) {  
        if(...) //satisfy your filter
            return true;  
        else  
            return false;  
}};  

Predicate<XXX> predicate2 = new Predicate<XXX>(){  
    @Override  
    public boolean apply(XXX input) {  
        if(...) //satisfy your filter
            return true;  
        else  
            return false;  
}};
Predicate allPredicates = Predicates.and(predicate1, predicate2);
//or Predicates.or(predicate1, predicate2);

Collection<XXX> list2 = Collections2.filter(list, allPredicates);

来源：https://stackoverflow.com/questions/6494614/guava-how-to-remove-from-a-list-based-on-a-predicate-keeping-track-of-what-w

标签

java

collections

filtering

Guava

predicate