firing a jQuery change function at document ready

问题

My change function allows users to switch from country to country and get different text and features. It works when changing country selections. But at initial page load, it does not fire jQuery change to set the hide and show text divs for the default / initial country.

Both divs display at initial page load. When I change away and then back to the default/initial country, change fires, hide and show fire, and shows the proper information and features.

I have tried document.ready with a change function both inside the switch selections and outside the change function. Neither work - they don't fire the hide, show and other jQuery in the switch cases at doc ready. Its not clear to me whether 'ready' is a valid trigger event.

I have also tried:

$('input[name=country]').value('US').trigger('click');

but it broke the change function. Here's the code. The country selection below is just 2 countries to keep it simple, but actually, there are many.

$(document).ready(function()
{
//1st tier - select country via radio buttons:           
//Initialize country
$('input[name=country]:first').attr('checked', true);   //Set first radio button (United States)
//$('input[name=country]:first').attr('checked', true).trigger('ready');  //sets 1st button, but does not fire change
//$('input[name=country]:first').trigger('click'); //sets 1st button, but does not fire change

$('input[name=country]').change(function ()
{                                                                               
// change user instructions to be country specific
    switch ($('input[name=country]:checked').val())
    {
        case 'US':
        $('#stateMessage1').text('2. Select a state or territory of the United States.');
        $('#stateMessage2').text('Start typing a state of the United States, then click on it in the dropdown box.');
        $('#threeSelects').show();
        $('#twoSelects').hide();
        //select via 3 steps                        
        break;           
        case 'CA':
        $('#stateMessage1').text('2. Select a province or territory of Canada.');
        $('#stateMessage2').text('Start typing a province of Canada, then click on it in the dropdown box.');
        $('#twoSelects').show();
        $('#threeSelects').hide();
        //select town via 2 steps - country, town           
        break;         
    }
});
});

回答1:

Just chain .trigger('change') to the end of the handler assignment.

 // ----------v-------v-----quotation marks are mandatory
$('input[name="country"]').change(function ()
{                                                                               
// change user instructions to be country specific
    switch ($('input[name="country"]:checked').val())
    {
        case 'US':
        $('#stateMessage1').text('2. Select a state or territory of the United States.');
        $('#stateMessage2').text('Start typing a state of the United States, then click on it in the dropdown box.');
        $('#threeSelects').show();
        $('#twoSelects').hide();
        //select via 3 steps                        
        break;           
        case 'CA':
        $('#stateMessage1').text('2. Select a province or territory of Canada.');
        $('#stateMessage2').text('Start typing a province of Canada, then click on it in the dropdown box.');
        $('#twoSelects').show();
        $('#threeSelects').hide();
        //select town via 2 steps - country, town           
        break;         
    }
}).trigger('change');  // <--- RIGHT HERE

Or if you only want it to fire on the first element, use triggerHandler() instead.

        // ...
        $('#twoSelects').show();
        $('#threeSelects').hide();
        //select town via 2 steps - country, town           
        break;         
    }
}).triggerHandler('change');  // <--- RIGHT HERE

回答2:

Why not just trigger change after selecting the appropriate radio buttons?

$('input[name=country]').change();

This is equivalent to

$('input[name=country]').trigger('change');

回答3:

Before the final });, add in $('input').change();

回答4:

This usually is made as:

function onChange ()
{                                                                               
    switch ($('input[name=country]:checked').val())
    ....
}

$('input[name=country]').change(onChange); // 1. attach it as event handler.
onChange();                                // 2. call it first time.

来源：https://stackoverflow.com/questions/6022732/firing-a-jquery-change-function-at-document-ready

标签

jquery

initialization

onchange