dispatch multiple actions in one effect

ぐ巨炮叔叔 提交于 2019-12-20 09:39:10

问题


I would like to diapatch two actions in one effect. Currently I have to declare two effects to achieve this :

  // first effect
  @Effect() action1$ = this.actions$
    .ofType(CoreActionTypes.MY_ACTION)
    .map(res => {
      return { type: "ACTION_ONE"}
    })
    .catch(() => Observable.of({
      type: CoreActionTypes.MY_ACTION_FAILED
    }));

  // second effect
  @Effect() action2$ = this.actions$
    .ofType(CoreActionTypes.MY_ACTION)
    .map(res => {
      return { type: "ACTION_TWO"}
    })
    .catch(() => Observable.of({
      type: CoreActionTypes.MY_ACTION_FAILED
    }));

Is it possible to have one action, be the source of two actions via a single effect ?


回答1:


@Effect()
loadInitConfig$ = this.actions$
    .ofType(layout.ActionTypes.LOAD_INIT_CONFIGURATION)
    .map<Action, void>(toPayload)
    .switchMap(() =>
        this.settingsService
            .loadInitConfiguration()
            .mergeMap((data: any) => [
                new layout.LoadInitConfigurationCompleteAction(data.settings),
                new meetup.LoadInitGeolocationCompleteAction(data.geolocation)
            ])
            .catch(error =>
                Observable.of(
                    new layout.LoadInitConfigurationFailAction({
                        error
                    })
                )
            )
    );



回答2:


You can use switchMap and Observable.of.

 @Effect({ dispatch: true }) action$ = this.actions$
    .ofType(CoreActionTypes.MY_ACTION)
    .switchMap(() => Observable.of(
        // subscribers will be notified
        {type: 'ACTION_ONE'} ,
        // subscribers will be notified (again ...)
        {type: 'ACTION_TWO'}
    ))
    .catch(() => Observable.of({
      type: CoreActionTypes.MY_ACTION_FAILED
    }));

Performance matters :

Instead of dispatching many actions that will trigger all the subscribers as many times as you dispatch, you may want to take a look into redux-batched-actions.

This allows you to warn your subscribers only when all of those multiple actions have been applied to the store.

For example :

@Effect({ dispatch: true }) action$ = this.actions$
    .ofType(CoreActionTypes.MY_ACTION)
    // subscribers will be notified only once, no matter how many actions you have
    // not between every action
    .map(() => batchActions([
        doThing(),
        doOther()
    ]))
    .catch(() => Observable.of({
      type: CoreActionTypes.MY_ACTION_FAILED
    }));



回答3:


If anyone wonders how to mix plain actions with ones from Observables.

I was stuck with same task, but small difference: I needed to dispatch two actions, with second one after API call, which made it an Observable. Something like:

  1. action1 is just an action: {type: 'ACTION_ONE'}
  2. action2 is API call mapped to action: Observable<{type: 'ACTION_TWO'}>

Following code solved my issue:

@Effect() action$ = this.actions$.pipe(
    ofType(CoreActionTypes.MY_ACTION),
    mergeMap(res =>
        // in order to dispatch actions in provided order
        concat(
            of(action1),
            action2
        )
    ),
    catchError(() => Observable.of({
        type: CoreActionTypes.MY_ACTION_FAILED
    }))
);

concat doc's




回答4:


You can choose mergeMap for async or concatMap for sync

  @Effect() action$ = this.actions$
    .ofType(CoreActionTypes.MY_ACTION)
    .mergeMap(() => Observable.from([{type: "ACTION_ONE"} , {type: "ACTION_TWO"}]))
    .catch(() => Observable.of({
      type: CoreActionTypes.MY_ACTION_FAILED
    }));



回答5:


you can also use .do() and store.next()

do allows you to attach a callback to the observable without affecting the other operators / changing the observable

e.g.

@Effect() action1$ = this.actions$
.ofType(CoreActionTypes.MY_ACTION)
.do(myaction => this.store.next( {type: 'ACTION_ONE'} ))
.switchMap((myaction) => Observable.of(
    {type: 'ACTION_TWO'}
))
.catch(() => Observable.of({
  type: CoreActionTypes.MY_ACTION_FAILED
}));

(you will need a reference to the store in your effects class)



来源:https://stackoverflow.com/questions/41701138/dispatch-multiple-actions-in-one-effect

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