String input xor encryption program

问题

Description:
I am trying to write a basic program for fun that will input a string/phrase then xor encrypt it and in the end cout the encrypted phrase. I am working on a mac so I will be compiling with xcode and running it in terminal.

Problem:
I am having an error with inputting a string that can be xor encrypted, see code below:

Code:

#include <iostream>
#include <string>
using namespace std;

int main ()
{
string mystr;
cout << "What's the phrase to be Encrypted? ";
//getline (cin, mystr);

char string[11]= getline (cin, mystr); //ERROR: Array must be initialized with brace-enclosed initializer
cout << "Phrase to be Encrypted: " << mystr << ".\n";
char key[11]="ABCDEFGHIJ";  //The Encryption Key, for now its generic
for(int x=0; x<10; x++)
{
    string[x]=mystr[11]^key[x];
    cout<<string[x];
}
return 0;
}

Help:
please identify and explain or provide examples why I am receiving the error code above.

回答1:

You're not calling getline correctly. You're also trying to use string as a variable when it's already defined as a type. I'd try something more like this:

getline(cin, mystr);

string result;

for (int i=0; i<10; i++) {
    result.push_back(mystr[i] ^ key[i]);
    cout << result[i];
}

回答2:

The return type of getline is a stream and you can't assign that to a char array. To initialize an array you have to use:

char s[10] = {'h', 'i', 0};

Or the shorthand for this in case of a char array:

char s[10] = "hi";

In your problem, you'd probably want to use the commented out getline statement and

const char* string = mystr.c_str();

来源：https://stackoverflow.com/questions/23588202/string-input-xor-encryption-program

标签

c++

encryption

xor