问题
I have a column with the name of a person in the following format: "LAST NAME, FIRST NAME"
- Only Upper Cases Allowed
- Space after comma optional
I would like to use a regular expression like: [A-Z]+,[ ]?[A-Z]+ but I do not know how to do this in T-SQL. In Oracle, I would use REGEXP_LIKE, is there something similar for SQL Server 2016?
I need something like the following:
UPDATE table
SET is_correct_format = 'YES'
WHERE REGEXP_LIKE(table.name,'[A-Z]+,[ ]?[A-Z]+');
回答1:
First, case sensitivity depends on the collation of the DB, though with LIKE
you can specify case comparisons. With that... here is some Boolean logic to take care of the cases you stated. Though, you may need to add additional clauses if you discover some bogus input.
declare @table table (Person varchar(64), is_correct_format varchar(3) default 'NO')
insert into @table (Person)
values
('LowerCase, Here'),
('CORRECTLY, FORMATTED'),
('CORRECTLY,FORMATTEDTWO'),
('ONLY FIRST UPPER, LowerLast'),
('WEGOT, FormaNUMB3RStted'),
('NoComma Formatted'),
('CORRECTLY, TWOCOMMA, A'),
(',COMMA FIRST'),
('COMMA LAST,'),
('SPACE BEFORE COMMA , GOOD'),
(' SPACE AT BEGINNING, GOOD')
update @table
set is_correct_format = 'YES'
where
Person not like '%[^A-Z, ]%' --check for non characters, excluding comma and spaces
and len(replace(Person,' ','')) = len(replace(replace(Person,' ',''),',','')) + 1 --make sure there is only one comma
and charindex(',',Person) <> 1 --make sure the comma isn't at the beginning
and charindex(',',Person) <> len(Person) --make sure the comma isn't at the end
and substring(Person,charindex(',',Person) - 1,1) <> ' ' --make sure there isn't a space before comma
and left(Person,1) <> ' ' --check preceeding spaces
and UPPER(Person) = Person collate Latin1_General_CS_AS --check collation for CI default (only upper cases)
select * from @table
回答2:
The tsql equivalent could look like this. I'm not vouching for the efficiency of this solution.
declare @table as table(name varchar(20), is_Correct_format varchar(5))
insert into @table(name) Values
('Smith, Jon')
,('se7en, six')
,('Billy bob')
UPDATE @table
SET is_correct_format = 'YES'
WHERE
replace(name, ', ', ',x')
like (replicate('[a-z]', charindex(',', name) - 1)
+ ','
+ replicate('[a-z]', len(name) - charindex(',', name)) )
select * from @table
The optional space is hard to solve, so since it's next to a legal character I'm just replacing with another legal character when it's there.
TSQL does not provide the kind of 'repeating pattern' of * or + in regex, so you have to count the characters and construct the pattern that many times in your search pattern.
I split the string at the comma, counted the alphas before and after, and built a search pattern to match.
Clunky, but doable.
来源:https://stackoverflow.com/questions/45698496/sql-server-2016-how-to-use-a-simple-regular-expression-in-t-sql