Django Ajax Form submit wrongly redirect to another page

问题

When I use ajax to submit a comment form in Django,the page will redirect to a blank page shows me the success data:

{"status":"success", "msg":"添加成功"}

,but not stay in current page.I want the page stay in current page and show me the new comment.

Here is my update_comment view:

def update_comment(request, news_pk):
    news = get_object_or_404(News, id=news_pk)
    comment_form = CommentForm(request.POST or None)
    if request.method == 'POST' and comment_form.is_valid():
        if not request.user.is_authenticated:
            return render(request, 'login.html', {})
        comments = comment_form.cleaned_data.get("comment")
        news_comment = NewsComments(user=request.user, comments=comments, news=news)
        news_comment.save()

    # return redirect(reverse('news:news_detail', kwargs={'news_pk': news.id}))
        return HttpResponse('{"status":"success", "msg":"添加成功"}', content_type='application/json')
    else:
        return HttpResponse('{"status":"fail", "msg":"添加失败"}', content_type='application/json')

Here is my ajax:

$(document).on('submit', 'comment_form', function(e){
        e.preventDefault();

        $.ajax({
            cache: false,
            type: "POST",
            url:"{% url 'operation:update_comment' news.id %}",
            data:{'news_pk':{{ news.id }}, 'comments':comments},
            async: true,
            beforeSend:function(xhr, settings){
                xhr.setRequestHeader("X-CSRFToken", "{{ csrf_token }}");
            },
            success: function(data) {
                if(data.status == 'fail'){
                    if(data.msg == '用户未登录'){
                        window.location.href="login";
                    }else{
                        alert(data.msg)
                    }
                }else if(data.status == 'success'){
                    window.location.reload();//refresh current page.
                }

                },
        });
    });

Here is my form:

<form id="comment_form" action="{%  url 'operation:update_comment' news.id %}" method="POST" >
{% csrf_token %}

<textarea id="comment_textarea"name="comment"></textarea>

<input type="submit" value="Submit"> </input>

</form>

回答1:

I have something similar in my project. Its a script to like a song. I'm just gonna put the relevant codes here.

The ajax script. I put this script in a separate file named like_script.html. I call it in a template using django template include

<script>
    $('#like').click(function(){
          $.ajax({
                   type: "POST",
                   url: "{% url 'song:like_song' %}",
                   data: {'pk': $(this).attr('pk'), 'csrfmiddlewaretoken': '{{ csrf_token }}'},
                   dataType: "json",
                   success: function(response) {
                          alert(response.message);
                    },
                    error: function(rs, e) {
                           alert(rs.responseText);
                    }
              }); 
        })
    </script>

The django view

import json
from django.http import HttpResponse
from django.contrib.auth.decorators import login_required
from django.views.decorators.http import require_POST
@login_required
@require_POST
def song_like_view(request):
    if request.method == 'POST':
        user = SiteUser.objects.get(user=request.user)
        pk = request.POST.get('pk', None)
        song = get_object_or_404(Song, pk=pk)

        if song.likes.filter(pk=user.pk).exists():
            song.likes.remove(user)
            song.like_count = song.likes.count()
            song.save(update_fields=['like_count'])
            message = "You unstarred this song.\n {} now has {} stars".format(song.title, song.like_count)
        else:
            song.likes.add(user)
            song.like_count = song.likes.count()
            song.save(update_fields=['like_count'])
            message = "You starred this song.\n {} now has {} stars".format(song.title, song.like_count)
    context = {'message' : message}
    return HttpResponse(json.dumps(context), content_type='application/json')

The url

urlpatterns = path("like/", views.song_like_view, name='like_song'),

The template where the script is called

    <a class="btn btn-sm btn-primary" href="" id="like" name="{{ song.pk }}" value="Like"></i> Unstar</a>
     {% include 'like_script.html' %}

Same button for like and unlike. I hope you can follow the logic to make yours right. Notice that in your view you don't need to include the pk. Just get it from the POST data pk = request.POST.get('pk', None)

回答2:

Finally I made it!Thanks Lord!Very excited!

I have Three major issues in my previous code.

First:Since the ajax will post the news_pk to the view update_comment,so I don't need add news_pk in this view's url and template(in the url of <form> tag and the url in the ajax),so I removed them,or the data will still pass through Form but not ajax.

Second:My binding is incorrect,I have the click handler on the form it should be a submit handler. If I was binding it to a button then I'd use click a handler.Ajax not work in Django post But for this part I'm still a some confused,between the button summit way and form submit way.

The third issue is I mistaked 'comments' and 'comment'.'comment' is the name attribute of <textarea> ,through which forms.py gets the data.

comments is defined by ajax through var comments = $("#js-pl-textarea").val(), so in the view I need use comments = request.POST.get("comments", "") but not comment,that's the reason why 'post failed'.

Following is my code.

Here is the ajax:

 $("#comment_form").submit(function(){
        var comments = $("#js-pl-textarea").val()

        $.ajax({
            cache: false,
            type: "POST",
            url:"{% url 'operation:update_comment' %}",
            data:{'news_pk':{{ news.pk }}, 'comments':comments},
            async: true,
            beforeSend:function(xhr, settings){
                xhr.setRequestHeader("X-CSRFToken", "{{ csrf_token }}");
            },
            success: function(data) {
                if(data.status == 'fail'){
                    if(data.msg == '用户未登录'){
                        window.location.href="login";
                    }else{
                        alert(data.msg)
                    }
                }else if(data.status == 'success'){
                    window.location.reload();//refresh current page.
                }

                },
        });
        return false;

    });

Here is my udate_comment view:

@login_required
def update_comment(request):
        news_pk = request.POST.get("news_pk", 0)
        comments = request.POST.get("comments", "")
        if int(news_pk) > 0 and comments:
            news_comments = NewsComments()
            news = News.objects.get(id=int(news_pk))
            news_comments.news = news
            news_comments.comments = comments
            news_comments.user = request.user
            news_comments.save()
            return HttpResponse('{"status":"success", "msg":"添加成功"}', content_type='application/json')
        else:
            return HttpResponse('{"status":"fail", "msg":"添加失败"}', content_type='application/json')

Here is my form in template:

<form id="comment_form" action="{%  url 'operation:update_comment'%}" method="POST" >
{% csrf_token %}

<textarea id="js-pl-textarea"name="comment"></textarea>

<input type="submit" value="Submit"> </input>

</form>

I really appreciate everyone's reply!With your reply I figured out these issue step by step!

来源：https://stackoverflow.com/questions/50051635/django-ajax-form-submit-wrongly-redirect-to-another-page

标签

ajax

django-forms

django-templates

django-views