问题
The default winforms Button control only draws itself in a "clicked state" when the user left clicks the button. I need the Button control to draw itself in the clicked state regardless of it was left clicked or right clicked. How would I accomplish this?
More specifically, I know I will need to derive a control from Button which extends the functionality, but I have no experience in extending functionality of winforms controls or drawing in GDI+. So I'm a little dumbfounded on what exactly I'll need to do once in there.
Thanks for the help.
回答1:
Standard button control sets the button in down and pressed mode using a private SetFlag
method. You can do it yourself too. I did it in following code:
using System.Windows.Forms;
public class MyButton : Button
{
protected override void OnMouseDown(MouseEventArgs e)
{
SetPushed(true);
base.OnMouseDown(e);
Invalidate();
}
protected override void OnMouseUp(MouseEventArgs e)
{
SetPushed(false);
base.OnMouseUp(e);
Invalidate();
}
private void SetPushed(bool value)
{
var setFlag = typeof(ButtonBase).GetMethod("SetFlag",
System.Reflection.BindingFlags.Instance |
System.Reflection.BindingFlags.NonPublic);
if(setFlag != null)
{
setFlag.Invoke(this, new object[] { 2, value });
setFlag.Invoke(this, new object[] { 4, value });
}
}
}
来源:https://stackoverflow.com/questions/42847448/winforms-button-right-click-visual-feedback-show-button-in-pushed-state