问题
Can I overload existing function/operator in existing class?
I was trying to do:
#include <iostream>
#include <string>
using namespace std;
string& string::operator<<(const string& str) {
this->append(str);
}
But this gives me error:
test.cpp:5: error: too few template-parameter-lists
How can I do this? Or I can't?
回答1:
You can't add member functions to a class unless you modify that class' definition. Use a free function instead:
string& operator<<(string & lhs, const string & rhs) {
return lhs += rhs;
}
回答2:
I defer to Benjamin's answer for creating a stream-like interface on a string
object. However, you could use a stringstream
instead.
#include <sstream>
std::istringstream ss;
ss << anything_you_want;
std::string s = ss.str(); // get the resulting string
ss.str(std::string()); // clear the string buffer in the stringstream.
This gives you the stream-like interface you want on a string
without needing to define a new function.
This technique can be used generally to extend the functionality of a string
. That is, defining a wrapper class that provides the extended functionality, and the wrapper class also provides access to the underlying string
.
来源:https://stackoverflow.com/questions/11515925/c-string-operator-overload