How to remove dir background in `ls -color` output

问题

I use default Linux Mint .bashrc, here is full bashrc, the output is like:

some dir has green background, How to remove it?

回答1:

To remove all background colors, stick the following into your ~/.bashrc :

eval "$(dircolors -p | \
    sed 's/ 4[0-9];/ 01;/; s/;4[0-9];/;01;/g; s/;4[0-9] /;01 /' | \
    dircolors /dev/stdin)"

回答2:

The explanation is given in the output of dircolors -p, e.g.,

Of course dircolors doesn't color its output. I used this script:

#!/usr/bin/perl -w

use strict;

our $comment = "\e[31m";
our $reset   = "\e[K\e[m";

our @data;

open my $fh, "dircolors -p|" or die "cannot read from dircolors";
@data = <$fh>;
close $fh;

printf "\e[H\e[2J";

for my $n ( 0 .. $#data ) {
    chomp $data[$n];
    if ( $data[$n] =~ /^\s*#/ ) {
        printf "%s%s%s\n", $comment, $data[$n], $reset;
    }
    elsif ( $data[$n] =~ /^\s*TERM\s/ ) {
        printf "%s\n", $data[$n];
    }
    elsif ( $data[$n] =~ /^\s*[^\s]+\s+\d+(;\d+)?\s*(#.*)?$/ ) {
        my $code = $data[$n];
        $code =~ s/^\s*[^\s]+\s+//;
        $code =~ s/\s.*//;
        my $data = $data[$n];
        $data =~ s/(#.*)$/$comment$1$reset/;
        $data =~ s/^(\s*)([^\s]+)(\s+)/$1\e[${code}m$2\e[m$3/;
        printf "%s\n", $data;
    }
    else {
        printf "%s\n", $data[$n];
    }
}

1;

To get rid of the background, you can either change the directory permissions, or use a different database to set your LS_COLORS environment variable. The dircolors documentation is the place to go.

来源：https://stackoverflow.com/questions/40574819/how-to-remove-dir-background-in-ls-color-output

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Linux

shell

terminal