Searching a log file [duplicate]

问题

Possible Duplicate:
Searching using Regex in VIM or elsewhere

I'm searching a huge ~600 Mb file for a particular pattern which is 7 Hexadecimal values long. The Problem is

the 'pattern' could be on the next line and
there are several addressing lines.

I got rid of problem 1 by getting rid of all the carriage returns but I'm still faced with even if the values are on the next line I have no idea how to search past the address line. Below is an example:
0x000001A0: 36 5B 09 76 99 31 55 09 78 99 34 51 49 BF E0 03
0x000001B0: 28 0B 0A 03 0B E0 07 28 0B 0A 03 0B 49 58 09 35

For example: I want to be able to find the pattern 49 BF E0 03 28 0B 0A, Which goes across lines 1 and 2 above but I can't just search for it regularly because of the 0x000001B0: at the beginning of the line Any suggestions or c++ code or excel ideas would be helpful. I'm using VIM at the moment to open this big file and using excel won't open the entire thing.

回答1:

Python, just read in line, split, chuck the first part, concat the hex into a string, and search. Something like this would work:

hex = ""
for each line in lines:
    tmp = line.split() // split on whitespace
    hex += tmp[1:] // grab everything after address

if hex.contains(pattern):
    # do something

Or use a regex, but you get the basic idea.

回答2:

You could use a circular buffer.

Open the file
Read a line
Read address and discart it
Read first value and put it into the buffer
Read next value, and throw last value of the buffer (std::list could be good for that)
Check if buffer contains the pattern
Loop through 5 up to the end of the line
Loop through 2 up to the end of the file

来源：https://stackoverflow.com/questions/6413361/searching-a-log-file

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c++

excel

vim