问题
I want
ereg ($rat, $dog, $cat)
to become
preg_match ('#'.$rat.'#', $dog, $cat)
To achieve this, I did
echo 'ereg ($rat, $dog, $cat)' | sed "s/ereg\(.*\)(\(.*\),/preg_match\1('#'.\2.'#',/g"
but, this regex changed the
ereg ($rat, $dog, $cat)
into
preg_match ('#'.$rat, $dog.'#', $cat)
instead of
preg_match ('#'.$rat.'#', $dog, $cat)
Can someone help me to build a regex that changes
ereg ($rat, $dog, $cat)
into
preg_match ('#'.$rat.'#', $dog, $cat)
回答1:
Just exclude ','...
echo 'ereg ($rat, $dog, $cat)' | sed "s/ereg\(.*\)(\([^,]*\),/preg_match\1('#'.\2.'#',/g"
回答2:
Note: This also works if you have multiple instances of ereg ($rat, $dog, $cat) on the same line whereas other answers do not:
$ echo 'ereg ($rat, $dog, $cat)' | sed "s/ereg\([^(]*\)(\([^,]*\),\([^)]*)\)/preg_match\1('#'.\2.'#',\3/g"
preg_match ('#'.$rat.'#', $dog, $cat)
Example
$ echo 'ereg ($rat, $dog, $cat) ereg ($rat, $dog, $cat)' | sed "s/ereg\([^(]*\)(\([^,]*\),\([^)]*)\)/preg_match\1('#'.\2.'#',\3/g"
preg_match ('#'.$rat.'#', $dog, $cat) preg_match ('#'.$rat.'#', $dog, $cat)
回答3:
~ ross$ echo 'ereg ($rat, $dog, $cat)' | sed -e "s/.*(\([^,]*\),\([^,]*\),\([^)]*\))/preg_match ('#'.\1.'#', \2, \3)/"
preg_match ('#'.$rat.'#', $dog, $cat)
回答4:
How about:
$ echo 'ereg ($rat, $dog, $cat)' | sed "s/ereg *(\([^,]*\), \([^,]*\)\([^)]*\))/preg_match('#'.\1.'#', \2\3)/g"
preg_match('#'.$rat.'#', $dog, $cat)
回答5:
I rather like Perl regexs (easier to write):
echo 'ereg ($rat, $dog, $cat)' | perl -pe 's/ereg\s*\(\s*(\$[^,]+),(.+)\)/preg_match("#" . $1 . "#", $2)/g'
or better (for PHP):
echo 'ereg ($rat, $dog, $cat)' | perl -pe 's/ereg\s*\(\s*(\$[^,]+),(.+)\)/preg_match("#{$1}#", $2)/g'
In sed, it would be:
echo 'ereg ($rat, $dog, $cat)' | sed -e 's/ereg\s*(\s*\(\$[^,]\+\),\(.\+\))/preg_match("#" . \1 . "#", \2)/'
Too many backslashes!!!
来源：https://stackoverflow.com/questions/4684760/greediness-in-sed