MySQL: ORDER BY with empty date '0000-00-00' as last but the rest ASC

问题

In our database, instead of making empty dates NULL, they are '0000-00-00' (I know, it sucks). How can I order these so that dates that are not '0000-00-00' are first and ordered ASC, and then the empty dates of '0000-00-00' come after?

Thanks!

回答1:

...
ORDER BY CASE WHEN YourDateColumn = '0000-00-00' THEN 2 ELSE 1 END,
         YourDateColumn

回答2:

Try Below :

  SELECT * FROM your_table ORDER BY (date_column='0000-00-00'), date_column ASC

OR

select * from your_table
order by if(date_column='0000-00-00',1,0),date_column;

回答3:

You can use a CASE WHEN http://dev.mysql.com/doc/refman/5.0/en/case-statement.html

... ORDER BY (CASE WHEN date = '0000-00-00' THEN 1 ELSE 0 END) ASC, otherColumns asc, ...

回答4:

ORDER BY (DateColumn = 0)
       , DateColumn

来源：https://stackoverflow.com/questions/9319553/mysql-order-by-with-empty-date-0000-00-00-as-last-but-the-rest-asc