问题
How do I return all the unique words from a text file using Python? For example:
I am not a robot
I am a human
Should return:
I
am
not
a
robot
human
Here is what I've done so far:
def unique_file(input_filename, output_filename):
input_file = open(input_filename, 'r')
file_contents = input_file.read()
input_file.close()
word_list = file_contents.split()
file = open(output_filename, 'w')
for word in word_list:
if word not in word_list:
file.write(str(word) + "\n")
file.close()
The text file the Python creates has nothing in it. I'm not sure what I am doing wrong
回答1:
for word in word_list:
if word not in word_list:
every word
is in word_list
, by definition from the first line.
Instead of that logic, use a set:
unique_words = set(word_list)
for word in unique_words:
file.write(str(word) + "\n")
set
s only hold unique members, which is exactly what you're trying to achieve.
Note that order won't be preserved, but you didn't specify if that's a requirement.
回答2:
Simply iterate over the lines in the file and use set to keep only the unique ones.
from itertools import chain
def unique_words(lines):
return set(chain(*(line.split() for line in lines if line)))
Then simply do the following to read all unique lines from a file and print them
with open(filename, 'r') as f:
print(unique_words(f))
回答3:
def unique_file(input_filename, output_filename):
input_file = open(input_filename, 'r')
file_contents = input_file.read()
input_file.close()
duplicates = []
word_list = file_contents.split()
file = open(output_filename, 'w')
for word in word_list:
if word not in duplicates:
duplicates.append(word)
file.write(str(word) + "\n")
file.close()
This code loops over every word, and if it is not in a list duplicates
, it appends the word and writes it to a file.
回答4:
This seems to be a typical application for a collection:
...
import collections
d = collections.OrderedDict()
for word in wordlist: d[word] = None
# use this if you also want to count the words:
# for word in wordlist: d[word] = d.get(word, 0) + 1
for k in d.keys(): print k
You could also use a collection.Counter(), which would also count the elements you feed in. The order of the words would get lost though. I added a line for counting and keeping the order.
回答5:
Using Regex and Set:
import re
words = re.findall('\w+', text.lower())
uniq_words = set(words)
Other way is creating a Dict and inserting the words like keys:
for i in range(len(doc)):
frase = doc[i].split(" ")
for palavra in frase:
if palavra not in dict_word:
dict_word[palavra] = 1
print dict_word.keys()
回答6:
string = "I am not a robot\n I am a human"
list_str = string.split()
print list(set(list_str))
回答7:
The problem with your code is word_list already has all possible words of the input file. When iterating over the loop you are basically checking if a word in word_list is not present in itself. So it'll always be false. This should work.. (Note that this wll also preserve the order).
def unique_file(input_filename, output_filename):
z = []
with open(input_filename,'r') as fileIn, open(output_filename,'w') as fileOut:
for line in fileIn:
for word in line.split():
if word not in z:
z.append(word)
fileOut.write(word+'\n')
回答8:
Use a set. You don't need to import anything to do this.
#Open the file
my_File = open(file_Name, 'r')
#Read the file
read_File = my_File.read()
#Split the words
words = read_File.split()
#Using a set will only save the unique words
unique_words = set(words)
#You can then print the set as a whole or loop through the set etc
for word in unique_words:
print(word)
回答9:
try:
with open("gridlex.txt",mode="r",encoding="utf-8")as india:
for data in india:
if chr(data)==chr(data):
print("no of chrats",len(chr(data)))
else:
print("data")
except IOError:
print("sorry")
来源:https://stackoverflow.com/questions/22978602/how-to-return-unique-words-from-the-text-file-using-python