Wrapping each type in a variadic template in a templated class

本秂侑毒 提交于 2019-12-19 05:53:46

问题


Given a variadic template Types..., I would like to store A<> for each of the types in the pack. This could be done in a tuple of A<>'s, but I'd need to programmatically derive the type of said tuple.

Is such a thing even possible in c++11/14/17?

template <class T> class A { };

template <class... Types>
class B
{
   // A tuple of A<>'s for each type in Types...
   std::tuple<A<Type1>, A<Type2>, ...> data;
};

回答1:


Simply with:

template <class... Types>
class B
{
   std::tuple<A<Types>...> data;
};


来源:https://stackoverflow.com/questions/32336822/wrapping-each-type-in-a-variadic-template-in-a-templated-class

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