XSLT - Replace apostrophe with escaped text in output

问题

I'm writing an XSLT template that need to output a valid xml file for an xml Sitemap.

<url>
<loc>
    <xsl:value-of select="umbraco.library:NiceUrl($node/@id)"/>
</loc>
<lastmod>
    <xsl:value-of select="concat($node/@updateDate,'+00:00')"/>
</lastmod>
</url>

Unfortunately, Url that is output contains an apostrophe - /what's-new.aspx

I need to escape the ' to ' for google Sitemap. Unfortunately every attempt I've tried treats the string ''' as if it was ''' which is invalid - frustrating. XSLT can drive me mad sometimes.

Any ideas for a technique? (Assume I can find my way around XSLT 1.0 templates and functions)

回答1:

So you have ' in your input, but you need the string   in your output?

In your XSL file, replace ' with &apos;, using this find/replace implementation (unless you are using XSLT 2.0):

<xsl:template name="string-replace-all">
  <xsl:param name="text"/>
  <xsl:param name="replace"/>
  <xsl:param name="by"/>
  <xsl:choose>
    <xsl:when test="contains($text,$replace)">
      <xsl:value-of select="substring-before($text,$replace)"/>
      <xsl:value-of select="$by"/>
      <xsl:call-template name="string-replace-all">
        <xsl:with-param name="text" select="substring-after($text,$replace)"/>
        <xsl:with-param name="replace" select="$replace"/>
        <xsl:with-param name="by" select="$by"/>
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="$text"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

Call it this way:

<loc>
  <xsl:call-template name="string-replace-all">
    <xsl:with-param name="text" select="umbraco.library:NiceUrl($node/@id)"/>
    <xsl:with-param name="replace" select="&apos;"/>
    <xsl:with-param name="by" select="&amp;apos;"/>
  </xsl:call-template>
</loc>

The problem is ' is interpreted by XSL as '. &apos; will be interpreted as '.

回答2:

The simple way to remove unwanted characters from your URL is to change the rules umbraco uses when it generates the NiceUrl.

Edit the config/umbracoSettings.config

add a rule to remove all apostrophes from NiceUrls like so:

<urlReplacing>
    ...
    <char org="'"></char>     <!-- replace ' with nothing -->
    ...
</urlReplacing>

Note: The contents of the "org" attribute is replaced with the contents of the element, here's another example:

<char org="+">plus</char> <!-- replace + with the word plus -->

回答3:

Have you tried setting disable-output-escaping to yes for your xsl:value-of element:

<xsl:value-of disable-output-escaping="yes" select="umbraco.library:NiceUrl($node/@id)"/>

Actually - this is probably the opposite of what you want.

How about wrapping the xsl:value-of in an xsl:text element?

<xsl:text><xsl:value-of select="umbraco.library:NiceUrl($node/@id)"/></xsl:text>

Perhaps you should try to translate ' to &apos;

回答4:

This will work, you just need to change TWO params as given below

<xsl:with-param name="replace">&apos;</xsl:with-param>
<xsl:with-param name="by" >AnyString</xsl:with-param>

来源：https://stackoverflow.com/questions/1103205/xslt-replace-apostrophe-with-escaped-text-in-output

标签

xml

xslt

sitemap