问题
I'm trying to create an input stream by doing this
InputStream is = (InputStream) getResources().openRawResource(R.drawable.image1);
but I'm met with the error "Expected resource of type raw" with respect to my drawable file (R.drawable.image1). image1 is a png and in my res/drawable folder.
Any ideas???
回答1:
@Broatian I don't currently have a res/raw folder. I found an alternative solution:
is = context.getResources().openRawResource(+ R.drawable.image1);
The + shows additional folders. Thanks for the help!
回答2:
If you want to open your png with this method then you have to put it in the res/raw folder. Then you'll be able to access the png using R.raw.image1.
Another alternative is to keep it in the drawable folder and then convert the drawable to a InputStream. See How to read drawable bits as InputStream
I assume you know how to get the drawable otherwise look at the Resources documentation.
回答3:
It is because They are expecting a raw type resource and you are passing a drawable type one. make a raw folder in the res folder and then put your image in the raw folder.
来源：https://stackoverflow.com/questions/25572647/android-openrawresource-not-working-for-a-drawable