Easiest way to know (programmatically) which resources folder is used based on screen density/size

问题

Is there a way to know exactly which layout (and other resources) are chosen by Android during runtime based on screen density and size when supporting multiple screens?

I need to know the folder's name.

EDIT:

I need to know the folder's name programmatically.

回答1:

If you're just doing this for debugging purposes, I'd recommend doing something like this: For each qualifier that you have a layout/drawable for, have a values folder with the same qualifier (e.g. if you have a layout-hdpi, also have a values-hdpi to match). Add a strings.xml for each of these folders, and define a string:

In values-hdpi:

<string name="folder_name">hdpi</string>

In values-xhdpi:

<string name="folder_name">xhdpi</string>

Then just resolve the string when you need it, and it will tell you which folder was selected.

回答2:

DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
switch(metrics.densityDpi){
                case DisplayMetrics.DENSITY_LOW:
                    break;
                case DisplayMetrics.DENSITY_MEDIUM:
                    break;
                case DisplayMetrics.DENSITY_HIGH:
                    break;
                case DisplayMetrics.DENSITY_XHIGH:
                    break;
                case DisplayMetrics.DENSITY_XXHIGH:
                    break;
                case DisplayMetrics.DENSITY_XXXHIGH:
                    break;
            }

回答3:

Imagine you have a structure like this:

res/
    drawable-mdpi/image.png
    drawable-hdpi/image.png
    drawable-xhdpi/image.png
    layout/main.xml
    layout-land/main.xml
    layout-xlarge/main.xml
    layout-sw600dp/main.xml

and you want to know, which layout is used.

One way would be to put a value in resources:

res/
    values-mdpi/strange_info.xml with:
        <string name="image_is_from_folder">drawable-mdpi</string>
    values-hdpi/strange_info.xml with:
        <string name="image_is_from_folder">drawable-hdpi</string>
    values-xhdpi/strange_info.xml with:
        <string name="image_is_from_folder">drawable-xhdpi</string>

    values/strange_info.xml with:
        <string name="main_is_from_folder">layout</string>
    values-land/strange_info.xml with:
        <string name="main_is_from_folder">layout-land</string>
    values-xlarge/strange_info.xml with:
        <string name="main_is_from_folder">layout-xlarge</string>
    values-sw600dp/strange_info.xml with:
        <string name="main_is_from_folder">layout-sw600dp</string>

In code you just do

String mainFolderName = context.getResources().getString(R.string.main_is_from_folder);

I have some doubts regarding -Xdpi qualifier, but it should work (not tested). Note that with the above structure you will get "drawable-hdpi" on ldpi devices for image.png.

回答4:

The layout is chosen based on how you program it. Same with the menu and values. The photos are based on the definition: HDPI = High definition, LDPI = Low definition ect.

来源：https://stackoverflow.com/questions/17157220/easiest-way-to-know-programmatically-which-resources-folder-is-used-based-on-s

标签

android

android-resources