How to wait for a child process to finish in Node.js?

问题

I'm running a Python script through a child process in Node.js, like this:

require('child_process').exec('python celulas.py', function (error, stdout, stderr) {
    child.stdout.pipe(process.stdout);
});

but Node doesn't wait for it to finish. How can I wait for the process to finish?

EDIT: Is it possible to do this by running the child process in a module I call from the main script?

回答1:

You should use exec-sync

That allow your script to wait that you exec is done

really easy to use:

var execSync = require('exec-sync');

var user = execSync('python celulas.py');

Take a look at: https://www.npmjs.org/package/exec-sync

回答2:

Use exit event for the child process.

var child = require('child_process').exec('python celulas.py')
child.stdout.pipe(process.stdout)
child.on('exit', function() {
  process.exit()
})

PS: It's not really a duplicate, since you don't want to use sync code unless you really really need it.

回答3:

NodeJS supports doing this synchronously. Use this:

const exec = require("child_process").execSync;

var result = exec("python celulas.py");

// convert and show the output.
    console.log(result.toString("utf8");

Remember to convert the buffer into a string. Otherwise you'll just be left with hex code.

回答4:

You need to remove the listeners exec installs to add to the buffered stdout and stderr, even if you pass no callback it still buffers the output. Node will still exit the child process in the buffer is exceeded in this case.

var child = require('child_process').exec('python celulas.py');
child.stdout.removeAllListeners("data");
child.stderr.removeAllListeners("data");
child.stdout.pipe(process.stdout);
child.stderr.pipe(process.stderr);

回答5:

In my opinion, the best way to handle this is by implementing an event emitter. When the first spawn finishes, emit an event that indicates that it is complete.

const { spawn } = require('child_process');
const events = require('events');
const myEmitter = new events.EventEmitter();


firstSpawn = spawn('echo', ['hello']);
firstSpawn.on('exit'), (exitCode) => {
    if (parseInt(code) !== 0) {
        //Handle non-zero exit
    }
    myEmitter.emit('firstSpawn-finished');
}

myEmitter.on('firstSpawn-finished', () => {
    secondSpawn = spawn('echo', ['BYE!'])
})

来源：https://stackoverflow.com/questions/22337446/how-to-wait-for-a-child-process-to-finish-in-node-js

标签

node.js

child-process