问题

I'm using IntelliJ IDEA 13.1.5, I used to work with Eclipse. I'm working on JavaFX application, I try to load FXML file within my MainApp class using getClass().getResource(). I read the documentation and I try several idea, at the end I have null.

This is the hierarchy :

dz.bilaldjago.homekode.MainApp.java

dz.bilaldjago.homekode.view.RootLayout.FXML

This is the code snippet I used:

FXMLLoader loader = new FXMLLoader();
loader.setLocation(getClass().getResource("view/RootLayout.fxml"));

I tried other solution such giving the url from the root and using the classLoader

the result is the same. Any idea please

回答1:

I solved this problem by pointing out the resource root on IDEA.

Right click on a directory (or just the project name) -> Mark directory As -> Resource Root.

Recompile & rejoice :P Hope this working for you~

回答2:

For those who use Intellij Idea: check for Settings -> Compiler -> Resource patterns.

The setting contains all extensions that should be interpreted as resources. If an extension does not comply to any pattern here, class.getResource will return null for resources using this extension.

回答3:

if your project is a maven project, check the target code to see whether your .fxml file exist there. if it's not there ,just add

<resources>
        <resource>
            <directory>src/main/java</directory>
            <includes>
                <include>**/*.xml</include>
            </includes>
            <filtering>true</filtering>
        </resource>
    </resources>

in your pom.xml

回答4:

TL; DR;

Put your resources in resources folder.
Use them with one slash before their names: getClass().getResource("/myfont.ttf");

Long Story;

If you are using Intellij IDEA and you created a Maven project, you should put your resources in resources folder (as marked as resource root by intellij itself) and these resource go to the root of your compiled app.

I mean, /resources/myfont.ttf will go to /myfont.ttf in the resulting build.

So you should get it via /myfont.ttf and not myfont.ttf. Use it like this:

getClass().getResource("/myfont.ttf");

No need to change anything else. Just this one helped me.

回答5:

I gave up trying to use getClass().getResource("BookingForm.css"));

Instead I create a File object, create a URL from that object and then pass it into getStyleSheets() or setLocation()File file = new File(System.getProperty("user.dir").toString() + "/src/main/resources/BookingForm.css");

scene.getStylesheets().add(folder.toURI().toURL().toExternalForm());

回答6:

Windows is case-sensitive, the rest of the world not. Also an executable java jar (zip format) the resource names are case sensitive.

Best rename the file

view/RootLayout.FXML

view/RootLayout.fxml

This must be done by moving the original file away, and creating a new one.

Also compile to a jar, and check that the fxml file was added to the jar (zip file). When not IntelliJ resource paths are treated by an other answer.

By the way this is path relative to the package path of getClass(). Be aware if you extended this class the full path changes, better use:

MainApp.class.getResource("view/RootLayout.fxml")

来源：https://stackoverflow.com/questions/26328040/intellij-idea-getclass-getresource-return-null

标签

java

intellij-idea

javafx

fxml

IntelliJ IDEA - getClass().getResource(“…”) return null

问题