What is i+++ increment in c++

问题

can anyone tell me what is the process of i+++ increment in c++.

回答1:

It is a syntax error.

Using the maximum munching rule i+++ is tokenized as:

i ++ +

The last + is a binary addition operator. But clearly it does not have two operands which results in parser error.

EDIT:

Question from the comment: Can we have i++++j ?

It is tokenized as:

i ++ ++ j

which again is a syntax error as ++ is a unary operator.

On similar lines i+++++j is tokenized by the scanner as:

i++ ++ + j

which is same as ((i++)++) + j which again in error as i++ is not a lvalue and using ++ on it is not allowed.

回答2:

i+++; will not compile. There is no operator +++ in C++.

i+++j, on the other hand, will compile. It will add i and j and then increment i. Because it is parsed as (i++)+j;

回答3:

if you mean i++ then its incrementing the value of i once its value has been read. As an example:

int i = 0;   // i == 0
int j = i++; // j == 0, i == 1

来源：https://stackoverflow.com/questions/5236706/what-is-i-increment-in-c