问题
I have a chain of operators on an RxJava observable. I'd like to be able to apply one of two operators depending on a boolean value without "breaking the chain".
I'm relatively new to Rx(Java) and I feel like there's probably a more idiomatic and readable way of doing this than my current approach of introducing a temporary variable.
Here's a concrete example, buffering items from an observable if a batch size field is non-null, otherwise emitting a single batch of unbounded size with toList()
:
Observable<Item> source = Observable.from(newItems);
Observable<List<Item>> batchedSource = batchSize == null ?
source.toList() :
source.buffer(batchSize);
return batchedSource.flatMap(...).map(...)
Is something like this possible? (pseudo-lambdas because Java):
Observable.from(newItems)
.applyIf(batchSize == null,
{ o.toList() },
{ o.buffer(batchSize) })
.flatMap(...).map(...)
回答1:
You can use compose(Func1)
to stay in-sequence but do custom behavior
source
.compose(o -> condition ? o.map(v -> v + 1) : o.map(v -> v * v))
.filter(...)
.subscribe(...)
来源:https://stackoverflow.com/questions/36058320/rxjava-how-to-conditionally-apply-operators-to-an-observable-without-breaking-t