Remove first N elements from a std::vector

问题

I can't seem to think of a reliable way (that also compacts memory) to remove the first N elements from a std::vector. How would one go about doing that?

回答1:

Since you mention that you want to compact memory, it would be best to copy everything to a new vector and use the swap idiom.

std::vector<decltype(myvector)::value_type>(myvector.begin()+N, myvector.end()).swap(myvector);

回答2:

Use the .erase() method:

// Remove the first N elements, and shift everything else down by N indices
myvec.erase(myvec.begin(), myvec.begin() + N);

This will require copying all of the elements from indices N+1 through the end. If you have a large vector and will be doing this frequently, then use a std::deque instead, which has a more efficient implementation of removing elements from the front.

回答3:

v.erase( v.begin(), v.size() > N ?  v.begin() + N : v.end() );

Don't forget the check of the size, just in case.

来源：https://stackoverflow.com/questions/7351899/remove-first-n-elements-from-a-stdvector