问题
Here, i want to achieve following
- Highlight all holidays in date-picker
- Disable specific days in date-picker
- Disable specific weekends in date-picker
I have snippets of each separately, but i want all together
Fiddle:Working Demo
Highlight holidays
var holydays = ['10/17/2013', '10/18/2013', '11/2/2013'];
function highlightDays(date) {
for (var i = 0; i < holydays.length; i++) {
if (new Date(holydays[i]).toString() == date.toString()) {
return [true, 'highlight'];
}
}
return [true, ''];
}
$(function () {
$("#dp").datepicker({
minDate: 0,
dateFormat: 'mm/dd/yy',
inline: true,
numberOfMonths: [1, 2],
dayNamesMin: ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'],
beforeShowDay: highlightDays,
});
});
Disable specific days
var disabledDays = ["10-20-2013", "10-21-2013", "11-15-2013", "11-17-2013"];
function disableAllTheseDays(date) {
var m = date.getMonth(), d = date.getDate(), y = date.getFullYear();
for (i = 0; i < disabledDays.length; i++) {
if($.inArray((m+1) + '-' + d + '-' + y,disabledDays) != -1) {
return [false];
}
}
return [true];
}
Disable Weekends
$(function() {
$( "#availability" ).datepicker({
minDate: 0,
dateFormat: 'mm/dd/yy',
inline: true,
numberOfMonths: [1, 2],
dayNamesMin: ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'],
beforeShowDay: $.datepicker.noWeekends
});
});
Could anyone help me..
Thanks in advance.
回答1:
change :
$(function () {
$("#dp").datepicker({
minDate: 0,
dateFormat: 'mm/dd/yy',
inline: true,
numberOfMonths: [1, 2],
dayNamesMin: ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'],
beforeShowDay: setCustomDate // <-----change function
});
});
add function :
function setCustomDate(date) {
var clazz = "";
var arr1 = highlightDays(date);
if (arr1[1] != "") clazz = arr1[1];
var arr2 = disableAllTheseDays(date);
var arr3 = $.datepicker.noWeekends(date);
return [(!arr2[0] || !arr3[0]) ? false : true, clazz];
}
回答2:
We are now in 2014, and a minimal code is required. Here is my way to disable days.
my variable 'specific' , 0 <= specific <= 7
in my demo :
1 = sunday
2 = saturday
4 = Monday to friday
if specific == 5 that mean 4 + 1 so i allow Monday till friday + sunday.
7 means all days allowed to pick. notice that I only allow to pick starting now to Month + 1
$( "#datepicker" ).datepicker({
minDate:0,
maxDate: '+1M-1D',
dateFormat: "yy-mm-dd",
beforeShowDay: function(date) {
var day = date.getDay();
if(day == 6)
return [(specific & 2) > 0, ''];
else if(day == 0)
return [(specific & 1) > 0, ''];
else
return [(specific & 4) > 0, ''];
}
});
回答3:
Just for future references. Since I was looking for the same thing and found these same function to disable days in a lot of different places:
http://www.spiceforms.com/blog/how-to-disable-dates-in-jquery-datepicker-a-short-guide/ https://davidwalsh.name/jquery-datepicker-disable-days
var disabledDays = ["10-20-2013", "10-21-2013", "11-15-2013", "11-17-2013"];
function disableAllTheseDays(date) {
var m = date.getMonth(), d = date.getDate(), y = date.getFullYear();
for (i = 0; i < disabledDays.length; i++) {
if($.inArray((m+1) + '-' + d + '-' + y,disabledDays) != -1) {
return [false];
}
}
return [true];
}
But since you're using inArray, the for is not needed, resulting in this simpler and more efficient function:
var disabledDays = ["4-2-2016", "4-4-2016"];
function disableAllTheseDays(date) {
var m = date.getMonth(), d = date.getDate(), y = date.getFullYear();
if($.inArray((m+1) + '-' + d + '-' + y,disabledDays) != -1) return [false];
return [true];
}
回答4:
This one works for me. Placed before closing body tag.
function DisableMonday(date) {
var day = date.getDay();
if (day == 1) {
return [false,"","Unavailable"] ;
} else {
return [true] ;
}
}
jQuery(function($){
$('input[name="datum"]').datepicker('option', 'beforeShowDay', DisableMonday).datepicker('refresh');
});
来源:https://stackoverflow.com/questions/19395558/highlight-disable-specific-days-in-jquery-ui-datepicker