问题
I am trying to configure a GPIO interrupt in the uboot, This it to test the Interrupt response time without any OS intervention (Bare-metal). I was able to configure the pin-muxing and also successful in setting up the interrupt with the GPIO pin.
My question is regarding the registering of the interrupt service routine. I see that the Interrupt vector table for my platform is at address 0xFFFF0000 ( I read the System Control Register to find out this). The interrupt Id for the GPIO was 56 and with that i just calculated the address where my interrupt service routine should reside and just tried writing the address with the pointer to my ISR routine. Is this the right way of doing it? or i have to take care of the all the other things like context saving etc by myself?
Note : I am using an ARM Cortex A-9.
Edit :
Based on the answers i went through the code i have the following questions. The definition of
do_irq for my architecture( arm v7) is not doing much and the CONFIG_USE_IRQ does not work for me since functions like arch_interrupt_init are not defined for me. So i can conclude interrupts are not supported for my architecture. Now If i have to define this on my own what all functions i need to implement to get this working? Since this is a very small part of my proj and i would want to see if i can do this is feasible to implement. I just want to know if this requires few lines of code or requires some effort to implement this interrupt support.
回答1:
The ARM vectors all interrupts to address 0xFFFF0018
(or 0x00000018
). This is typically an unconditional branch. Then the code will inspect some interrupt controller hardware to determine the number 56. Typically, there is a routine to set the handler for the interrupt number, so you don't manually patch the code; this table is dependent on how the u-boot
interrupt handling is implemented.
In my u-boot
sourcenote, the interrupt table looks like this,
.globl _start
_start:
b reset
ldr pc, _undefined_instruction
ldr pc, _software_interrupt
ldr pc, _prefetch_abort
ldr pc, _data_abort
ldr pc, _not_used
ldr pc, _irq
ldr pc, _fiq
...
_irq:
.word irq
So _irq
is a label to install a routine for interrupt handling; it does some assembler in the same file and then calls do_irq()
, based on CONFIG_USE_IRQ. Part of the API is in *lib_arm/interrupts.c*. Some CPUs are defined to handler irqs, such as cpu/arm720t/interrupts.c, for a S3C4510B. Here you can see that the code gets a register from this controller and then branches to a table.
So by default u-boot
doesn't seem to have support for interrupts. This is not surprising as a boot loader is usually polling based for simplicity and speed.
Note: My u-boot
is base on 2009.01-rc3.
来源:https://stackoverflow.com/questions/15829601/enabling-interrupts-in-u-boot-for-arm-cortex-a-9