问题
I am trying to convert string in following format: 20130817T140000Z(17th Aug 2013 at 14:00) to epoch time (seconds since 1970) in an MS Excel 2013.
Tried cell formatting, but it doesn't work with T and Z or the format in general.
回答1:
This will convert your date into somethign Excel will understand, If you have your date in Cell A1, Then convert that into Epoch Time
=(DATE(LEFT(A1,4),MID(A1,5,2),MID(A1,7,2)) + TIME(MID(A1,10,2),MID(A1,12,2),MID(A1,14,2))-25569)*86400)
回答2:
Try this:
A1=20130817T140000Z
A2=DATE(LEFT(A1,4),MID(A1,5,2),MID(A1,7,2))
A3=(DATEDIF("01/01/1970 00:00:00",A2,"D")+TIME(MID(A1,10,2),MID(A1,12,2),MID(A1,14,2)))*24*60*60
A1 is your input date as text, A2 is a formatted date, and A3 is a seconds difference between your date and epoch start date.
Useful link
Update: based on @user2140261 suggestions.
回答3:
Assuming the string to convert is in cell B1 you can use the following with a custom format on the cell to get the date/time.
=DATE(MID(B1,1,4),MID(B1,5,2),MID(B1,7,2))+TIME(MID(B1,10,2),MID(B1,12,2),MID(B1,14,2))
The custom format is:
dd/mm/yyyy hh:mm:ss
回答4:
This will get you the date with accuracy to the minute. You can follow the pattern to get seconds if necessary.
=DATE(VALUE(LEFT(A1,4)),VALUE(RIGHT(LEFT(A1,6),2)),VALUE(RIGHT(LEFT(A1,8),2)))+VALUE(RIGHT(LEFT(A1,11),2))/24+VALUE(RIGHT(LEFT(A1,13),2))/(24*60)
回答5:
You could use this version to convert your string to Epoch time
=(TEXT(LEFT(A1,8)&MID(A1,10,6),"0000-00-00 00\:00\:00")-25569)*86400
This uses TEXT function to convert your string into a string that looks like a valid date/time - when you subtract 25569 (1/1/1970) that will co-erce that string to a valid date/time and the result can be multiplied by the number of seconds in a day to get Epoch time
来源：https://stackoverflow.com/questions/21557018/convert-string-to-a-epoch-time-in-excel