Check that the contents of one NSArray are all in another array

问题

I have one NSArray with names in string objects like this:@[@"john", @"smith", @"alex", @"louis"], and I have another array that contains lots of names. How can I check that all the objects in the first array are in the second?

回答1:

NSSet has the functionality that you are looking for.

If we disregard performance issues for a moment, then the following snippet will do what you need in a single line of code:

BOOL isSubset = [[NSSet setWithArray: array1] isSubsetOfSet: [NSSet setWithArray: mainArray]];

回答2:

Use this code..

NSArray *temp1 = [NSArray arrayWithObjects:@"john",@"smith",@"alex",@"loui,@"Jac", nil];
NSArray *temp2 = [NSArray arrayWithObjects:@"john",@"smith",@"alex",@"loui,@"Rob", nil];

NSMutableSet *telephoneSet = [[NSMutableSet alloc] initWithArray:temp1] ;
NSMutableSet *telephoneSet2 = [[NSMutableSet alloc] initWithArray:temp2];


[telephoneSet intersectSet:telephoneSet2];

 NSArray *outPut = [telephoneSet allObjects];
 NSLog(@"%@",outPut);

output array contains..

"john","smith","alex","loui

as per ur requirement.

回答3:

Run a loop and use isEqualToStiring to verify whether array1 objects exists in mainArray.

回答4:

int num_of_matches = 0;
for(NSString *name in mainArray)
{
      if(array1 containsObject:name){
      num_of_matches++;
     }
}
if(num_of_matches == [array1 count]{
      // All objects present
}else {
      // Matched number is equal of number_of_matches
}

回答5:

If you just need to check if all objects from array1 are in mainArray, you should just use NSSet e.g.

BOOL isSubset = [[NSSet setWithArray:array1] isSubsetOfSet:[NSSet setWithArray:mainArray]]

if you need to check which objects are in mainArray, you should take a look at NSMutableSet

NSMutableSet *array1Set = [NSMutableSet setWithArray:array1];
[array1Set intersectSet:[NSSet setWithArray:mainArray]];
//Now array1Set contains only objects which are present in mainArray too

回答6:

Use NSArray filteredArrayUsingPredicate: method. Its really fast to find out similar types of object in both arrays

NSPredicate *intersectPredicate = [NSPredicate predicateWithFormat:@"SELF IN %@", otherArray];
NSArray *intersectArray = [firstArray filteredArrayUsingPredicate:intersectPredicate];

From above code intersect array gives you same objects which are in other array.

回答7:

Try this way;

NSArray *mainArray=@[@"A",@"B",@"C",@"D"];
NSArray *myArray=@[@"C",@"x"];

BOOL result=YES;
for(id object in myArray){
    if (![mainArray containsObject:object]) {
        result=NO;
        break;
    }
}
NSLog(@"%d",result); //1 means contains, 0 means not contains

回答8:

You can use the concept of [NSArray containsObject:], where your objects will be from your array1 like you say "john","smith","alex","loui"

回答9:

 NSArray *array1 = [NSArray arrayWithObjects:@"a", @"u", @"b", @"v", @"c", @"f", nil];
    NSMutableArray *mainArray = [NSMutableArray arrayWithObjects:@"a", @"u", @"I", @"G", @"O", @"W",@"Z",@"C",@"T", nil];
    int j=0;
    for(int i=0; i < mainArray.count; i++)
    {
        if (j < array1.count)
        {
            for( j=0; j <= i; j++)
            {
                if([[mainArray objectAtIndex:i] isEqualToString:[array1 objectAtIndex:j]] )
                {
                    NSLog(@"%@",[mainArray objectAtIndex:i]);
                }
            }
        }

    }

来源：https://stackoverflow.com/questions/15269301/check-that-the-contents-of-one-nsarray-are-all-in-another-array

标签

objective-c

cocoa

cocoa-touch

collections

nsarray