Floating point precision in Python array

问题

I apologize for the really simple and dumb question; however, why is there a difference in precision displayed for these two cases?

>> test = numpy.array([0.22])
>> test2 = test[0] * 2
>> test2
0.44

>> test = numpy.array([0.24])
>> test2 = test[0] * 2
>> test2
0.47999999999999998

I'm using python2.6.6 on 64-bit linux. Thank you in advance for your help.

This also hold seems to hold for a list in python

>>> t = [0.22]
>>> t
[0.22]

>>> t = [0.24]
>>> t
[0.23999999999999999]

回答1:

Because they are different numbers and different numbers have different rounding effects.

(Practically any of the Related questions down the right-hand side will explain the cause of the rounding effects themselves.)

Okay, more serious answer. It appears that numpy performs some transformation or calculation on the numbers in an array:

>>> t = numpy.array([0.22])
>>> t[0]
0.22


>>> t = numpy.array([0.24])
>>> t[0]
0.23999999999999999

whereas Python doesn't automatically do this:

>>> t = 0.22
>>> t
0.22

>>> t = 0.24
>>> t
0.24

The rounding error is less than numpy's "eps" value for float, which implies that it should be treated as equal (and in fact, it is):

>>> abs(numpy.array([0.24])[0] - 0.24) < numpy.finfo(float).eps
True

>>> numpy.array([0.24])[0] == 0.24
True

But the reason that Python displays it as '0.24' and numpy doesn't is because Python's default float.__repr__ method uses lower precision (which, IIRC, was a pretty recent change):

>>> str(numpy.array([0.24])[0])
0.24

>>> '%0.17f' % 0.24
'0.23999999999999999'

来源：https://stackoverflow.com/questions/5160339/floating-point-precision-in-python-array

标签

python

numpy

precision