jquery event listen on position changed

笑着哭i 提交于 2019-12-18 06:08:44

问题


I need to listen to an elements relative position. This is particular useful for dynamic layouting issues. There is no option to listen for CSS styles of even position() or offset() attributes.

Why: The relative position can change if a sibling change its dimension inside dialogs or forms (re-layout). So for interactive forms this can help to use i.e. the maximum available height or width of the parent or something like that.


回答1:


This custom jquery extension listens for object position by timer poll. I.m.o. there is no way to solve this without a timer, because position may be changed without jquery being invoked at all (i.e. re-layouting sibling elements). This solution watches the elements .position() and .offset() values. It can be easily improved to watch .css() styles or other stuff that is not covered by jQuery events.

jQuery extension:

jQuery.fn.onPositionChanged = function (trigger, millis) {
    if (millis == null) millis = 100;
    var o = $(this[0]); // our jquery object
    if (o.length < 1) return o;

    var lastPos = null;
    var lastOff = null;
    setInterval(function () {
        if (o == null || o.length < 1) return o; // abort if element is non existend eny more
        if (lastPos == null) lastPos = o.position();
        if (lastOff == null) lastOff = o.offset();
        var newPos = o.position();
        var newOff = o.offset();
        if (lastPos.top != newPos.top || lastPos.left != newPos.left) {
            $(this).trigger('onPositionChanged', { lastPos: lastPos, newPos: newPos });
            if (typeof (trigger) == "function") trigger(lastPos, newPos);
            lastPos = o.position();
        }
        if (lastOff.top != newOff.top || lastOff.left != newOff.left) {
            $(this).trigger('onOffsetChanged', { lastOff: lastOff, newOff: newOff});
            if (typeof (trigger) == "function") trigger(lastOff, newOff);
            lastOff= o.offset();
        }
    }, millis);

    return o;
};

Call it by:

$("#<SOME_ID>").onPositionChanged(function(){alert("foobar")});



回答2:


This is my solution which is based on willsteel solution. I had to monitor the changes to the width and offsetWidth. This will trigger the function even if the element has become invisible/visible due to any reason.

See updated code below:

jQuery.fn.onPositionChanged = function (trigger, millis) {
    if (millis == null) millis = 100;
    var o = $(this[0]); // our jquery object
    if (o.length < 1) return o;
    var lastPos = null;
    var lastOff = null;
    var lastWidth = null;
    var lastOffWidth = null;
    setInterval(function () {
        if (o == null || o.length < 1) return o; // abort if element is non existend eny more
        if (lastPos == null) lastPos = o.position();
        if (lastOff == null) lastOff = o.offset();
        if (lastWidth == null) lastWidth = o.width();
        if (lastOffWidth == null) lastOffWidth = o[0].offsetWidth;
        var newPos = o.position();
        var newOff = o.offset();
        var newWidth = o.width();
        var newOffWidth = o[0].offsetWidth;
        if (lastPos.top != newPos.top || lastPos.left != newPos.left) {
            $(this).trigger('onPositionChanged', { lastPos: lastPos, newPos: newPos });
            if (typeof (trigger) == "function") trigger(lastPos, newPos);
            lastPos = o.position();
        }
        if (lastOff.top != newOff.top || lastOff.left != newOff.left) {
            $(this).trigger('onPositionChanged', { lastOff: lastOff, newOff: newOff});
            if (typeof (trigger) == "function") trigger(lastOff, newOff);
            lastOff= o.offset();
        }
        if (lastWidth != newWidth) {
            $(this).trigger('onPositionChanged', { lastWidth: lastWidth, newWidth: newWidth});
            if (typeof (trigger) == "function") trigger(lastWidth, newWidth);
            lastWidth= o.width();
        }
        if (lastOffWidth != newOffWidth) {
            $(this).trigger('onPositionChanged', { lastOffWidth: lastOffWidth, newOffWidth: newOffWidth});
            if (typeof (trigger) == "function") trigger(lastOffWidth, newOffWidth);
            lastWidth= o.width();
        }
    }, millis);
    return o;
};



回答3:


My variant of code above that will work on multiple objects and based on any selector, but it does not work with jQuery exactly.

var onPositionChanged = function (selector,trigger, millis) {
if (millis == null) millis = 200;
setInterval(function(){
    var o_s = jQuery(selector); // our jquery object
    if (o_s.length < 1) return o_s;

    for(var i = 0; i<o_s.length; i++)
    {
        var o = o_s.eq(i);

        var lastPos = jQuery(o).attr("lastPos");
        var lastOff = jQuery(o).attr("lastOff");
        lastPos = ((lastPos == "" || lastPos == undefined) ? null : JSON.parse(lastPos));
        lastOff = ((lastOff == "" || lastOff == undefined) ? null : JSON.parse(lastOff));
        setTimeout(function (o) {
            if (o == null || o.length < 1) return o; // abort if element is non existend eny more
            if (lastPos == null) lastPos = o.position();
            if (lastOff == null) lastOff = o.offset();
            var newPos = o.position();
            var newOff = o.offset();
            if (lastPos.top != newPos.top || lastPos.left != newPos.left) {
                jQuery(this).trigger('onPositionChanged', { lastPos: lastPos, newPos: newPos });
                if (typeof (trigger) == "function") trigger(o,lastPos, newPos);
                lastPos = o.position();
                jQuery(o).attr("lastPos",JSON.stringify(lastPos));
            }
            if (lastOff.top != newOff.top || lastOff.left != newOff.left) {
                jQuery(this).trigger('onOffsetChanged', { lastOff: lastOff, newOff: newOff});
                if (typeof (trigger) == "function") trigger(o,lastOff, newOff);
                lastOff= o.offset();
                jQuery(o).attr("lastOff",JSON.stringify(lastOff));
            }
        }, millis,o);
    }
},millis);

};

Usage example:

jQuery(document).ready(function(){
onPositionChanged(".grid-item:not(.d-none)",function(object){

    var left_percentage = parseInt(jQuery(object).position().left / jQuery(object).parent().width() * 100);
    var parent_width = jQuery(object).parent().width();

    var percentage_of_parent = parseInt(jQuery(object).width() / parent_width * 100);

    if(left_percentage > 74 && percentage_of_parent >= 25
    || left_percentage > 66 && percentage_of_parent >= 33
    || left_percentage > 49 && percentage_of_parent >= 50)
    {
        jQuery(object).find(".card").css("margin-right","0px");
        jQuery(object).parent().masonry('layout');
    }
    if(left_percentage < 1)
    {
        jQuery(object).find(".card").css("margin-left","0px");
        jQuery(object).parent().masonry('layout');
    }
});

});



来源:https://stackoverflow.com/questions/18743144/jquery-event-listen-on-position-changed

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