Dealing with NAs when calculating mean (summarize_each) on group_by

问题

I have a data frame md:

md <- data.frame(x = c(3,5,4,5,3,5), y = c(5,5,5,4,4,1), z = c(1,3,4,3,5,5),
      device1 = c("c","a","a","b","c","c"), device2 = c("B","A","A","A","B","B"))
md[2,3] <- NA
md[4,1] <- NA
md

I want to calculate means by device1 / device2 combinations using dplyr:

library(dplyr)
md %>% group_by(device1, device2) %>% summarise_each(funs(mean))

However, I am getting some NAs. I want the NAs to be ignored (na.rm = TRUE) - I tried, but the function doesn't want to accept this argument. Both these lines result in error:

md %>% group_by(device1, device2) %>% summarise_each(funs(mean), na.rm = TRUE)
md %>% group_by(device1, device2) %>% summarise_each(funs(mean, na.rm = TRUE))

回答1:

The other answers showed you the syntax for passing mean(., na.rm = TRUE) into summarize/_each.

Personally, I deal with this so often and it's so annoying that I just define the following convenience set of NA-aware basic functions (e.g. in my .Rprofile), such that you can apply them with dplyr with summarize(mean_) and no pesky arg-passing; also keeps the source-code cleaner and more readable, which is another strong plus:

mean_   <- function(...) mean(..., na.rm=T)
median_ <- function(...) median(..., na.rm=T)
sum_    <- function(...) sum(..., na.rm=T)
sd_     <- function(v)   sqrt(sum_((v-mean_(v))^2) / length(v))
cor_    <- function(...) cor(..., use='pairwise.complete.obs')
table_  <- function(...) table(..., useNA='ifany')
mode_   <- function(...) {
  tab <- table(...)
  names(tab[tab==max(tab)]) # the '==' implicitly excludes NA values
}
clamp_  <- function(..., minval=0, maxval=70) pmax(minval, pmin(maxval,...))

Really you want to be able to flick one global switch once and for all, like na.action/na.pass/na.omit/na.fail to tell functions as default behavior what to do, and not throw errors or be inconsistent, as they currently do, across different packages.

There used to be a CRAN package called Defaults for setting per-function defaults but it is not maintained since 2014, pre-3.x . For more about it Setting Function Defaults R on a Project Specific Basis

回答2:

try:

 library(dplyr)
 md %>% group_by(device1, device2) %>%
        summarise_each(funs(mean(., na.rm = TRUE)))

回答3:

Simple as that:

funs(mean(., na.rm = TRUE))

来源：https://stackoverflow.com/questions/31060105/dealing-with-nas-when-calculating-mean-summarize-each-on-group-by

标签

dplyr

mean