问题
This is based on the code presented in this SO : Write an Rx "RetryAfter" extension method
I am using the code by Markus Olsson (evaluation only at the moment), and before anyone asks I have tried to get hold of Markus on Github, but that is blocked where I work, so I felt the only thing I could do was ask here at SO. Sorry about that, if this sits badly with any one.
So I am using the following code, in a small demo which is this:
class Attempt1
{
private static bool shouldThrow = true;
static void Main(string[] args)
{
Generate().RetryWithBackoffStrategy(3,
MyRxExtensions.ExponentialBackoff,
ex =>
{
return ex is NullReferenceException;
}, Scheduler.TaskPool)
.Subscribe(
OnNext,
OnError
);
Console.ReadLine();
}
private static void OnNext(int val)
{
Console.WriteLine("subscriber value is {0} which was seen on threadId:{1}",
val, Thread.CurrentThread.ManagedThreadId);
}
private static void OnError(Exception ex)
{
Console.WriteLine("subscriber bad {0}, which was seen on threadId:{1}",
ex.GetType(),
Thread.CurrentThread.ManagedThreadId);
}
static IObservable<int> Generate()
{
return Observable.Create<int>(
o =>
{
Scheduler.TaskPool.Schedule(() =>
{
if (shouldThrow)
{
shouldThrow = false;
Console.WriteLine("ON ERROR NullReferenceException");
o.OnError(new NullReferenceException("Throwing"));
}
Console.WriteLine("Invoked on threadId:{0}",
Thread.CurrentThread.ManagedThreadId);
Console.WriteLine("On nexting 1");
o.OnNext(1);
Console.WriteLine("On nexting 2");
o.OnNext(2);
Console.WriteLine("On nexting 3");
o.OnNext(3);
o.OnCompleted();
Console.WriteLine("On complete");
Console.WriteLine("Finished on threadId:{0}",
Thread.CurrentThread.ManagedThreadId);
});
return () => { };
});
}
}
public static class MyRxExtensions
{
/// <summary>
/// An exponential back off strategy which starts with 1 second and then 4, 9, 16...
/// </summary>
public static readonly Func<int, TimeSpan>
ExponentialBackoff = n => TimeSpan.FromSeconds(Math.Pow(n, 2));
public static IObservable<T> RetryWithBackoffStrategy<T>(
this IObservable<T> source,
int retryCount = 3,
Func<int, TimeSpan> strategy = null,
Func<Exception, bool> retryOnError = null,
IScheduler scheduler = null)
{
strategy = strategy ?? MyRxExtensions.ExponentialBackoff;
int attempt = 0;
return Observable.Defer(() =>
{
return ((++attempt == 1) ? source : source.Delay(strategy(attempt - 1), scheduler))
.Select(item => new Tuple<bool, T, Exception>(true, item, null))
.Catch<Tuple<bool, T, Exception>, Exception>(e =>
retryOnError(e)
? Observable.Throw<Tuple<bool, T, Exception>>(e)
: Observable.Return(new Tuple<bool, T, Exception>(false, default(T), e)));
})
.Retry(retryCount)
.SelectMany(t => t.Item1
? Observable.Return(t.Item2)
: Observable.Throw<T>(t.Item3));
}
}
The code makes sense to me, we try and do an operation if that fails we back off and retry. The exception type that we want to retry can be specified, and we also see that the subscriber only sees the final values once after retry which works (in the demo code above the Exception is only done (OnError'd the first time)).
So generally the code works as expected except for one thing.
If I look at the output the code above produces I get this:
ON ERROR NullReferenceException
Invoked on threadId:10
On nexting 1
Invoked on threadId:11
On nexting 1
On nexting 2
On nexting 3
On complete
Finished on threadId:10
On nexting 2
On nexting 3
On complete
Finished on threadId:11
subscriber value is 1 which was seen on threadId:10
subscriber value is 2 which was seen on threadId:10
subscriber value is 3 which was seen on threadId:10
The interesting thing for me here is that the subscriber values all come in one go, I would have expected that when the OnNext within the Generate() method were called that the Subscribers OnNext would write the OnNext'ed value to the Console output.
Could anyone shed any light on why this might be?
回答1:
It's because you are putting a Delay on the result stream. (The value for n passed to ExponentialBackoff on the second iteration is 1, giving a delay of 1 second.)
Delay operates on source, but the source proceeds as normal. Delay schedules the results it receives to be emitted after the specified duration. So the subscriber is getting the results after the logic of Generate has run to completion.
If you think about it this is how Delay must be - otherwise Delay would be able to somehow interfere with upstream operators!
It is possible to interfere with upstream operators (without throwing exceptions), by being a slow consumer. But that would certainly be a very bad way for a simple Delay to behave.
I don't think the Delay is what you intend here - because Delay doesn't delay it's subscription. If you use DelaySubscription instead, you'll get what you're after I think. This is what's used in the linked question too.
Your question provides a great illustration of the difference between Delay and DelaySubscription! It's worth thinking about Defer in here too.
The distinction between these three is subtle but significant, so let's summarize all three:
Delay- Calls target operator immediately to get anIObservable, on itsSubscribecallsSubscribeon target immediately, schedules events for delivery after specified delay on the specifiedScheduler.DelaySubscription- Calls target operator immediately to get anIObservable. On itsSubscribeschedulesSubscribeon target for execution after specified delay on the specifiedScheduler.Defer- Has no target operator. OnSubscriberuns provided factory function to get targetIObservableand immediately callsSubscribe. There's no delay added, hence noSchedulerto specify.
回答2:
For anyone else that happens upon this post, it was indeed fixed by suggestions made by James World, and Brandon (thanks chaps).
Here is full working code
class Attempt1
{
private static bool shouldThrow = true;
static void Main(string[] args)
{
Generate().RetryWithBackoffStrategy(3, MyRxExtensions.ExponentialBackoff,
ex =>
{
return ex is NullReferenceException;
}, Scheduler.TaskPool)
.Subscribe(
OnNext,
OnError
);
Console.ReadLine();
}
private static void OnNext(int val)
{
Console.WriteLine("subscriber value is {0} which was seen on threadId:{1}",
val, Thread.CurrentThread.ManagedThreadId);
}
private static void OnError(Exception ex)
{
Console.WriteLine("subscriber bad {0}, which was seen on threadId:{1}",
ex.GetType(),
Thread.CurrentThread.ManagedThreadId);
}
static IObservable<int> Generate()
{
return Observable.Create<int>(
o =>
{
Scheduler.TaskPool.Schedule(() =>
{
if (shouldThrow)
{
shouldThrow = false;
Console.WriteLine("ON ERROR NullReferenceException");
o.OnError(new NullReferenceException("Throwing"));
}
Console.WriteLine("Invoked on threadId:{0}",
Thread.CurrentThread.ManagedThreadId);
Console.WriteLine("On nexting 1");
o.OnNext(1);
Console.WriteLine("On nexting 2");
o.OnNext(2);
Console.WriteLine("On nexting 3");
o.OnNext(3);
o.OnCompleted();
Console.WriteLine("On complete");
Console.WriteLine("Finished on threadId:{0}",
Thread.CurrentThread.ManagedThreadId);
});
return () => { };
});
}
}
public static class MyRxExtensions
{
/// <summary>
/// An exponential back off strategy which starts with 1 second and then 4, 9, 16...
/// </summary>
public static readonly Func<int, TimeSpan> ExponentialBackoff = n => TimeSpan.FromSeconds(Math.Pow(n, 2));
public static IObservable<T> RetryWithBackoffStrategy<T>(
this IObservable<T> source,
int retryCount = 3,
Func<int, TimeSpan> strategy = null,
Func<Exception, bool> retryOnError = null,
IScheduler scheduler = null)
{
strategy = strategy ?? MyRxExtensions.ExponentialBackoff;
int attempt = 0;
return Observable.Defer(() =>
{
return ((++attempt == 1) ? source : source.DelaySubscription(strategy(attempt - 1), scheduler))
.Select(item => new Tuple<bool, T, Exception>(true, item, null))
.Catch<Tuple<bool, T, Exception>, Exception>(e =>
retryOnError(e)
? Observable.Throw<Tuple<bool, T, Exception>>(e)
: Observable.Return(new Tuple<bool, T, Exception>(false, default(T), e)));
})
.Retry(retryCount)
.SelectMany(t => t.Item1
? Observable.Return(t.Item2)
: Observable.Throw<T>(t.Item3));
}
public static IObservable<T> DelaySubscription<T>(this IObservable<T> source,
TimeSpan delay, IScheduler scheduler = null)
{
if (scheduler == null)
{
return Observable.Timer(delay).SelectMany(_ => source);
}
return Observable.Timer(delay, scheduler).SelectMany(_ => source);
}
}
Which produces the desired output of
ON ERROR NullReferenceException
Invoked on threadId:11
On nexting 1
On nexting 2
On nexting 3
On complete
Finished on threadId:11
Invoked on threadId:11
On nexting 1
subscriber value is 1 which was seen on threadId:11
On nexting 2
subscriber value is 2 which was seen on threadId:11
On nexting 3
subscriber value is 3 which was seen on threadId:11
On complete
Finished on threadId:11
来源：https://stackoverflow.com/questions/20189166/rx-back-off-and-retry