difference between parseInt() and parseFloat() [duplicate]

问题

Possible Duplicate:
Behavior difference between parseInt() and parseFloat()

var box  = $('.box'),
fontSize = parseInt(box.css('font-size'), 10) + 5;

 $('button').on('click', function() {
  box.animate({fontSize: fontSize});
});

//..

 var box  = $('.box'),
 fontSize = parseFloat(box.css('font-size'), 10) + 5;

  $('button').on('click', function() {
    box.animate({fontSize: fontSize})
});

what the difference between..

**fontSize = parseInt(box.css('font-size'), 10);**

**fontSize = parseFloat(box.css('font-size'), 10);**

and and why should put 10 as a context..Please Help?

回答1:

JavaScript provides two methods for converting non-number primitives into numbers: parseInt() and parseFloat() . As you may have guessed, the former converts a value into an integer whereas the latter converts a value into a floating-point number.

Any number literal contained in a string is also converted correctly, so the string "0xA" is properly converted into the number 10. However, the string "22.5" will be converted to 22 , because the decimal point is an invalid character for an integer. Some examples:

var iNum1 = parseInt("1234blue"); //returns 1234

var iNum2 = parseInt("0xA"); //returns 10

var iNum3 = parseInt("22.5"); //returns 22

var iNum4 = parseInt("blue"); //returns NaN

The parseInt() method also has a radix mode, allowing you to convert strings in binary, octal, hexadecimal, or any other base into an integer. The radix is specified as a second argument to parseInt() , so a call to parse a hexadecimal value looks like this:

var iNum1 = parseInt("AF", 16); //returns 175

Of course, this can also be done for binary, octal, and even decimal (which is the default mode):

var iNum1 = parseInt("10", 2); //returns 2

var iNum2 = parseInt("10", 8); //returns 8

var iNum2 = parseInt("10", 10); //returns 10

If decimal numbers contain a leading zero, it’s always best to specify the radix as 10 so that you won’t accidentally end up with an octal value. For example:

var iNum1 = parseInt("010"); //returns 8

var iNum2 = parseInt("010", 8); //returns 8

var iNum3 = parseInt("010", 10); //returns 10

In this code, both lines are parsing the string "010" into a number. The first line thinks that the string is an octal value and parses it the same way as the second line (which specifies the radix as 8). The last line specifies a radix of 10, so iNum3 ends up equal to 10.

Another difference when using parseFloat() is that the string must represent a floating-point number in decimal form, not octal or hexadecimal. This method ignores leading zeros, so the octal number 0908 will be parsed into 908 , and the hexadecimal number 0xA will return NaN because x isn’t a valid character for a floating-point number. There is also no radix mode for parseFloat() .

Some examples of using parseFloat() :

var fNum1 = parseFloat("1234blue"); //returns 1234

var fNum2 = parseFloat("0xA"); //returns 0

var fNum3 = parseFloat("22.5"); //returns 22.5

var fNum4 = parseFloat("22.34.5"); //returns 22.34

var fNum5 = parseFloat("0908"); //returns 908

var fNum6 = parseFloat("blue"); //returns NaN

回答2:

First of all only parseInt accepts second argument. It's called radix. It represents numeral system to be used. In example you can convert number into binary or hexadecimal code.

parseFloat only accepts one argument.

来源：https://stackoverflow.com/questions/12812863/difference-between-parseint-and-parsefloat

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