问题
Is there any way to absolutely position a div relatively to its sibling? For example: Inside a div there are two other divs - div1 and div2. I want to absolutely position div2 relatively to div1.
回答1:
Absolute positioning is dependent on the "current positioning context", which may include a parent element (if absolutely or relatively positioned) but will never include a sibling element.
Can you reorganize your dom so that you have a parent-child instead of siblings? If so, you could set the parent's position to relative or absolute and the child's position to absolute and the child's position would remain absolute in relation to the parent.
回答2:
There is no way using absolute position, according to w3c specification:
In the absolute positioning model, a box is explicitly offset with respect to its containing block
— relatively to parent block, not to sibling one
And no way to use relative positioning, also according to to w3c specification:
Once a box has been laid out according to the normal flow or floated, it may be shifted relative to this position.
— relatively to block's position, not to sibling block
summary:
Nobody can solve problem you described
回答3:
Try it with jquery
<script type="text/javascript">
$('#div2').css('margin-left', $('#div1').outerWidth() +XXX + 'px');
回答4:
Depending on your needs, you can float them or position both absolute with appropriate left/top/right/bottom values.
Post your markup and explain exactly what you're trying to achieve.
来源：https://stackoverflow.com/questions/10624771/css-sibling-absolute-positioning