C strcat - warning: passing arg 2 of `strcat' makes pointer from integer without a cast

问题

I'm having a problem with the program below. I'm trying to scan through a string command entered by the user for certain words. My major issue right now is that when I run the following I get a warning saying that "passing arg 2 of `strcat' makes pointer from integer without a cast". My intent is to loop through the first three characters of the string "s", concatenate them onto a string "firstthree", and later check the value of the string "firstthree". Any help is appreciated.

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <readline/readline.h>
#include <readline/history.h>

/* Simple example of using gnu readline to get lines of input from a user.
Needs to be linked with -lreadline -lcurses
add_history tells the readline library to add the line to it's
internal histiry, so that using up-arrow (or ^p) will allows the user
to see/edit previous lines.
*/

int main(int argc, char **argv) {
    char *s;
    while (s=readline("Enter Name: ")) {
            add_history(s); /* adds the line to the readline history buffer */
            printf("Hello %s\n",s);/*output message to the user*/
            char *firstthree;
            int i;
            for(i = 0; i < 3; i++){
                    strcat(firstthree, s[i]);
                    printf("Hello %s\n",firstthree);//checking to see the character added to the end of the string
            }
            printf("Hey %s\n",firstthree);/*prints out the first three characters*/
            free(s); /* clean up! */
            free(firstthree);
    }
    return(0);
}

回答1:

Your program has a lot of problems; you never initialize firstthree, for example.

The reason you're getting the specific error you're seeing is because of this call:

strcat(firstthree, s[i]);

s is a char *, so s[i] is a char, but strcat expects both parameters to be pointers to null-terminated strings. What it seems you want is something like:

char firstthree[4] = { 0 };
for (int i = 0; i < 3; i++)
{
    firstthree[i] = s[i];
    printf("Hello %s\n", firstthree);
}

回答2:

You can't use strcat() to do this; it requires two char* s as arguments, not a char* and a char. You could use strncat() if it is available on your platform.

来源：https://stackoverflow.com/questions/19307600/c-strcat-warning-passing-arg-2-of-strcat-makes-pointer-from-integer-without

标签

strcat