Python - Count number of words in a list strings

问题

Im trying to find the number of whole words in a list of strings, heres the list

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"]

expected outcome:

There are 4 words in mylist[0], 1 in mylist[1] and so on

for x, word in enumerate(mylist):
    for i, subwords in enumerate(word):
        print i

Totally doesnt work....

What do you guys think?

回答1:

Use str.split:

>>> mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
>>> for item in mylist:
...     print len(item.split())
...     
4
1
2
3

回答2:

The simplest way should be

num_words = [len(sentence.split()) for sentence in mylist]

回答3:

You can use NLTK:

import nltk
mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"]
print(map(len, map(nltk.word_tokenize, mylist)))

Output:

[4, 1, 2, 3]

回答4:

for x,word in enumerate(mylist):
    print len(word.split())

回答5:

a="hello world aa aa aa abcd  hello double int float float hello"
words=a.split(" ")
words
dic={}
for word in words:
    if dic.has_key(word):
        dic[word]=dic[word]+1
    else:
        dic[word]=1
dic

回答6:

We can count the number of a word's ocurrence in a list using the Counter function.

from collection import Counter

string = ["mahesh","hello","nepal","nikesh","mahesh","nikesh"]

count_each_word = Counter(string)
print(count_each_word)

Output:

Counter({mahesh:2},{hello:1},{nepal:1},{nikesh:2})

回答7:

This is another solution:

You can clean your data first and then count the result, something like that:

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
for item in mylist:
    for char in "-.,":
        item = item.replace(char, '')
        item_word_list = item.split()
    print(len(item_word_list))

The result:

来源：https://stackoverflow.com/questions/18827198/python-count-number-of-words-in-a-list-strings

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python

string

list

counter