问题
I wrote an assembly that is assemble with:
$as --32 -o hello.o hello.s
Then I tried to generate an executable with:
$ld -o hello hello.o
It gives me an error:
ld: i386 architecture of input file `ConditionalBranching.o' is incompatible with i386:x86-64 output
I tried using flag -m32 or --32, but ld dont take them. I cannot find a solution by reading the man page of ld. How can I generate a 32-bit binary from my 32-bit shared object?
回答1:
Your linker is attempting to create a 64-bit binary, but your assembly code was assembled for a 32-bit architecture. This creates a mismatch.
Fix this by passing the -m elf_i386 flag to your linker, explicitly instructing it to create a 32-bit binary.
来源：https://stackoverflow.com/questions/30184929/use-ld-on-64-bit-platform-to-generate-32-bit-executable