Underscore is not working in oracle like clause

问题

When development, I used 'test_1%' to find 'test_123' in like. But in production environment its not working. Using 'escape '\'' is working. is there any setting needs to set in oracle? I want to use without escape '\''.

回答1:

try this in SQL Developer:

SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%' escape '\'

in sql plus:

set escape '\'
SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%';

回答2:

In Oracle, you can also use ESCAPE like this:

SELECT * FROM name_of_table WHERE description LIKE 'testing\_%' ESCAPE '\';

回答3:

The other answers using the ESCAPE '\' didn't work for me, but I was able to overcome this issue by using a REPLACE function:

SELECT * FROM name_of_table WHERE REPLACE(description, '_', '~') LIKE 'testing~%';

来源：https://stackoverflow.com/questions/21380261/underscore-is-not-working-in-oracle-like-clause