问题
In order to return to app after call, I use telprompt instead of tel. Codes like this:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt://10086"]];
Somebody says that it will be rejected by apple because telpromt is not the public URL Scheme. But I didn't find a certain answer - Yes or No. Can anybody help me?
回答1:
You may want to have a look at handleopenurl.com an index for iOS URL schemes.
I do not know telprompt. Why not just use tel://10086?
回答2:
I noticed that with iOS 8.0 the tel:// URL scheme will also return to the app after the call. The only difference now is that with telprompt:// the app will prompt before starting the call.
回答3:
telprompt:// and tel:// are both valid custom URL scheme of iOS, for now.
Since Apple does not have documentation on telprompt, its functionality may be removed without notice (low chance though).
Note: Their behavior is different. The former one is better, as it won't dial the number directly and won't stay at Phone app after call.
回答4:
This will not get your application rejected as I already uploaded an application with this and it is on the App Store now.
来源：https://stackoverflow.com/questions/11608940/will-apps-that-use-telprompt-be-rejected