Android HashMap in Bundle?

时光毁灭记忆、已成空白 提交于 2019-12-17 17:33:55

问题


The android.os.Message uses a Bundle to send with it's sendMessage-method. Therefore, is it possible to put a HashMap inside a Bundle?


回答1:


try as:

Bundle extras = new Bundle();
extras.putSerializable("HashMap",hashMap);
intent.putExtras(extras);

and in second Activity

Bundle bundle = this.getIntent().getExtras();

if(bundle != null) {
   hashMap = bundle.getSerializable("HashMap");
}

because Hashmap by default implements Serializable so you can pass it using putSerializable in Bundle and get in other activity using getSerializable




回答2:


According to the doc, Hashmap implements Serializable, so you can putSerializable I guess. Did you try it ?




回答3:


Please note: If you are using a AppCompatActivity, you will have to call the protected void onSaveInstanceState(Bundle outState) {} (NOT public void onSaveInstanceState(Bundle outState, PersistableBundle outPersistentState) {}) method.

Example code...

Store the map:

@Override
protected void onSaveInstanceState(Bundle outState) {
    super.onSaveInstanceState(outState);
    outState.putSerializable("leftMaxima", leftMaxima);
    outState.putSerializable("rightMaxima", rightMaxima);
}

And receive it in onCreate:

if (savedInstanceState != null) {
    leftMaxima = (HashMap<Long, Float>) savedInstanceState.getSerializable("leftMaxima");
    rightMaxima = (HashMap<Long, Float>) savedInstanceState.getSerializable("rightMaxima");
}

Sorry if it's some kind of a duplicate answer - maybe someone will find it useful. :)




回答4:


If you want to send all the keys in the bundle, you can try

for(String key: map.keySet()){
    bundle.putStringExtra(key, map.get(key));
}



回答5:


  public static Bundle mapToBundle(Map<String, Object> data) throws Exception {
    Bundle bundle = new Bundle();
    for (Map.Entry<String, Object> entry : data.entrySet()) {
        if (entry.getValue() instanceof String)
            bundle.putString(entry.getKey(), (String) entry.getValue());
        else if (entry.getValue() instanceof Double) {
            bundle.putDouble(entry.getKey(), ((Double) entry.getValue()));
        } else if (entry.getValue() instanceof Integer) {
            bundle.putInt(entry.getKey(), (Integer) entry.getValue());
        } else if (entry.getValue() instanceof Float) {
            bundle.putFloat(entry.getKey(), ((Float) entry.getValue()));
        }
    }
    return bundle;
}



回答6:


I am using my kotlin implementation of Parcelable to achieve that and so far it works for me. It is useful if you want to avoid the heavy serializable.

Also in order for it to work, I recommend using it with these

Declaration

class ParcelableMap<K,V>(val map: MutableMap<K,V>) : Parcelable {
    constructor(parcel: Parcel) : this(parcel.readMap(LinkedHashMap<K,V>()))

    override fun writeToParcel(parcel: Parcel, flags: Int) {
        parcel.writeMap(map)
    }

    override fun describeContents(): Int {
        return 0
    }

    companion object CREATOR : Parcelable.Creator<ParcelableMap<Any?,Any?>> {
        @JvmStatic
        override fun createFromParcel(parcel: Parcel): ParcelableMap<Any?,Any?> {
            return ParcelableMap(parcel)
        }
        @JvmStatic 
        override fun newArray(size: Int): Array<ParcelableMap<Any?,Any?>?> {
            return arrayOfNulls(size)
        }
    }

}

Use

write

val map = LinkedHashMap<Int, String>()
val wrap = ParcelableMap<Int,String>(map)
Bundle().putParcelable("your_key", wrap)

read

val bundle = fragment.arguments ?: Bundle()
val wrap = bundle.getParcelable<ParcelableMap<Int,String>>("your_key")
val map = wrap.map

Don't forget that if your map K,V are not parceled by default they must implement Parcelable




回答7:


In Kotlin:

hashMap = savedInstanceState?.getSerializable(ARG_HASH_MAP) as? HashMap<Int, ValueClass>

putSerializable(ARG_HASH_MAP, hashMap)


来源:https://stackoverflow.com/questions/11452859/android-hashmap-in-bundle

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