问题
I often use this list command in Unix (AIX / KSH):
ls -Artl
It displays the files as this:
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test1.txt-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test2.txt
I would like to modify the command such a way that the full path of the file is displayed. For example:
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test1.txt-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test2.txt
Any ideas?
I found several resolution methods using pwd or find but - as far as I see - this does not work work if I want to keep the ls options.
回答1:
What about this trick...
ls -lrt -d -1 $PWD/{*,.*}
OR
ls -lrt -d -1 $PWD/*
I think this has problems with empty directories but if another poster has a tweak I'll update my answer. Also, you may already know this but this is probably be a good candidate for an alias given it's lengthiness.
[update] added some tweaks based on comments, thanks guys.
[update] as pointed out by the comments you may need to tweek the matcher expressions depending on the shell (bash vs zsh). I've re-added my older command for reference.
回答2:
Try this, works for me: ls -d /a/b/c/*
回答3:
Use this command:
ls -ltr /mig/mthome/09/log/*
instead of:
ls -ltr /mig/mthome/09/log
to get the full path in the listing.
回答4:
I use this command:
ls -1 | xargs readlink -f
回答5:
optimized from spacedrop answer ...
ls $(pwd)/*
and you can use ls options
ls -alrt $(pwd)/*
回答6:
You can combine the find command and the ls command. Use the path (.) and selector (*) to narrow down the files you're after. Surround the find command in back quotes. The argument to -name is doublequote star doublequote in case you can't read it.
ls -lart `find . -type f -name "*" `
来源：https://stackoverflow.com/questions/5580828/unix-ls-command-show-full-path-when-using-options