How do I pass a function as a parameter to in elisp?

问题

I'm trying to pass one method to another in elisp, and then have that method execute it. Here is an example:

(defun t1 ()
  "t1")

(defun t2 ()
  "t1")

(defun call-t (t)
  ; how do I execute "t"?
  (t))

; How do I pass in method reference?
(call-t 't1)

回答1:

First, I'm not sure that naming your function t is helping as 't' is used as the truth value in lisp.

That said, the following code works for me:

(defun test-func-1 ()  "test-func-1"
   (interactive "*")
   (insert-string "testing callers"))

(defun func-caller (callee)
  "Execute callee"
  (funcall callee))

(func-caller 'test-func-1)

Please note the use of 'funcall', which triggers the actual function call.

回答2:

The note at the end of this page says that you can quote functions with #' instead of ' to signal to the byte compiler that the symbol always names a function.

来源：https://stackoverflow.com/questions/213267/how-do-i-pass-a-function-as-a-parameter-to-in-elisp