问题
In asynchronous JavaScript, it is easy to run tasks in parallel and wait for all of them to complete using Promise.all
:
async function bar(i) {
console.log('started', i);
await delay(1000);
console.log('finished', i);
}
async function foo() {
await Promise.all([bar(1), bar(2)]);
}
// This works too:
async function my_all(promises) {
for (let p of promises) await p;
}
async function foo() {
await my_all([bar(1), bar(2), bar(3)]);
}
I tried to rewrite the latter in python:
import asyncio
async def bar(i):
print('started', i)
await asyncio.sleep(1)
print('finished', i)
async def aio_all(seq):
for f in seq:
await f
async def main():
await aio_all([bar(i) for i in range(10)])
loop = asyncio.get_event_loop()
loop.run_until_complete(main())
loop.close()
But it executes my tasks sequentially.
What is the simplest way to await multiple awaitables? Why doesn't my approach work?
回答1:
The equivalent would be using asyncio.wait:
import asyncio
async def bar(i):
print('started', i)
await asyncio.sleep(1)
print('finished', i)
async def main():
await asyncio.wait([bar(i) for i in range(10)])
loop = asyncio.get_event_loop()
loop.run_until_complete(main())
loop.close()
Why doesn't my approach work?
Because when you await
each item in seq
, you block that coroutine. So in essence, you have synchronous code masquerading as async. If you really wanted to, you could implement your own version of asyncio.wait
using loop.create_task
or asyncio.ensure_future
.
EDIT
As Andrew mentioned, you can also use asyncio.gather.
回答2:
I noticed that asyncio.gather() may be a better way to await other than asyncio.wait() if we want ordered results.
As the docs indicates, the order of result values from asyncio.gather() method corresponds to the order of awaitables in aws. However, the order of result values from asyncio.wait() won't do the same thing.You can test it.
来源:https://stackoverflow.com/questions/34377319/combine-awaitables-like-promise-all